Login or Sign Up

The efficiency of a machine is 60℅. Calculate the work done by a student who used this machine to lift a load of 150kg through a distance of 2.5cm

How do we work it

I don't I don't know how to work it that is why I'm asked trying to ask you to help me

Please help me to do the work 🥺🥺

150 * 0.025 / 0.60 = ____

How did you get the answer

Help me

Hep

The efficiency of a machine is 60℅,find In joules the work done by a student using the machine to rise a load of 150kg through a vertical distance or 2.5 m (g=10m/s2)

Help me solve this question please

I don't know how to solve it

Similar Questions

wo machines are monitored for their efficiency. Machine A puts out 250J of work for every 800J of work input. Machine B provides

Top answer: Machine A is more efficient. Read more.
Two machines are monitored for their efficiency. Machine A puts out 250J of work for every 800J of work input. Machine B

Top answer: To determine which machine is more efficient, we can compare the output work to the input work for Read more.
Calculate the efficiency of a machine that produces 800J of work for every 2000J of work placed into the machine, and show your

Top answer: Efficiency is calculated using the formula: Efficiency = (Output/Input) * 100% Given that the Read more.
A machine raises a load of 600N through a height of 1.5m when an effort of 100N moves a total distance of 20m.(a) calculate the

Top answer: a) Fd = 600*1.5 b) 6:1 c) Fd ideal/Fd actual Read more.
a machine was used to lift a load of 30N through a distance of 2metres. the effort applied was 10N through a distance of

Top answer: A machine was Read more.
A load of 500N is raised through 5m by a machine when it's effort E moves simultaneously through a distance of 25m along it's

Top answer: output work = 500 * 5 = 2500 Joules work in = work out/.8 = 2500/.8 = 3125 Joules E * 25 = 3125 E= Read more.
Use the table to answer the question.Machine Output Work (J) Input Work (J) A 750 1,500 B 1,000 4,000 C 450 600 D 3,000 5,000

Top answer: machine C Read more.
Use the table to answer the question.Machine Output Work (J) Input Work (J) A 750 1,500 B 1,000 4,000 C 450 600 D 3,000 5,000

Top answer: machine C Read more.
Use the table to answer the question.Machine Output Work (J) Input Work (J) A 750 1,500 B 1,000 4,000 C 450 600 D 3,000 5,000

Top answer: machine D Read more.
Use the table to answer the question.Machine Output Work (J) Input Work (J) A 750 1,500 B 1,000 4,000 C 450 600 D 3,000 5,000

Top answer: The efficiency of a machine is determined by the ratio of output work to input work. For machine A, Read more.

Did you know?

Did you know that the efficiency of a machine determines how much useful work it can accomplish? In this case, a machine with an efficiency of 60% means that only 60% of the input energy is converted into useful work. Hence, if a student used this machine to lift a load of 150kg through a distance of 2.5cm, the work done by the student would be calculated as follows: Work = Force x Distance The force exerted by the student is equal to the weight of the load, which is mass x gravity. Assuming a standard gravity of 9.8m/s², the force would be 150kg x 9.8m/s² = 1470N. Now, considering the distance of 2.5cm, it needs to be converted to meters by dividing it by 100: 2.5cm / 100 = 0.025m. Substituting the values into the work formula: Work = 1470N x 0.025m = 36.75 joules. Therefore, the student performed approximately 36.75 joules of work to lift the 150kg load using a machine with a 60% efficiency.