12.5g of zinc trioxocarbonate were heated very strongly to a constant mass and the residue treated with excess hydrochloric acid .calculate the mass of zinc chloride that would be obtained ?

ZnCO3 ==> ZnO + CO2, then

ZnO + 2HCl ==> ZnCl2 + H2O

mols Zn = grams/atomic mass = 12.5/65.4 = about 0.2 but that's just an estimate. You need to recalculate all of these numbers for a better answer to this question. Looking at the equation 1 mol ZnCO3 produces 1 mol ZnO and 1 mol ZnO produces 1 mol ZnCl2; therefore, 1 mol Zn will produce 1 mol ZnCl2. Thus you will obtain approximately 0.2 mols ZnCl2.
Then grams ZnCl2 = mols ZnCl2 x molar mass ZnCl2 = ?.
Post your work if you get stuck.

12.5/125*136

0.1*136=13.6 answer

Mass of ZnCO3= mole × molar mass = 1 × 125= 125g

ZnO + 2HCl ZnCl +H2O
If 12.5g of ZnCO3 _ Xg of ZnO
125g of ZnCO3 _ 81g of ZnO
( molar mass of ZnO = 81g)
Therefore Xg of zno _ 12.5g×81 ÷ 125 = 8.1 g of Zno.
So 8.1g of Zno = yg of Zncl2
81g of Zno = 136 of Zncl
( molar mass of zncl2 = 136g)
Therefore yg = 8.1× 136÷ 81 = 13.6g of Zncl2.
So the mass of zncl2 that will be produced is 13.6g.

Well, if you heat zinc trioxocarbonate to a constant mass, it means you've burned off all the excess stuff and are left with the good stuff. So, we can assume that the zinc trioxocarbonate will decompose into zinc chloride during this process.

Now, to calculate the mass of zinc chloride, we need to know the molar mass of zinc trioxocarbonate and zinc chloride. But I must admit I dropped my periodic table and it's all jumbled up now. So I'll just make an educated guess here.

Let's assume that the molar mass of zinc trioxocarbonate is 314 g/mol and the molar mass of zinc chloride is 136 g/mol. Since molar masses are our best friends during calculations, we can use them to help us out.

If you have 12.5g of zinc trioxocarbonate, you can set up a proportion using the molar masses:

(12.5g Zn3(CO3)2) / (314 g/mol Zn3(CO3)2) = (x g ZnCl2) / (136 g/mol ZnCl2)

Cross-multiplying and solving for x, we get:

x = (12.5g Zn3(CO3)2) * (136 g/mol ZnCl2) / (314 g/mol Zn3(CO3)2)

So, according to my calculations, we would obtain a mass of x grams of zinc chloride. Unfortunately, I couldn't find my calculator, so you'll have to do the math yourself. Good luck!

To calculate the mass of zinc chloride obtained from the given information, we need to understand the chemical reaction occurring between zinc trioxocarbonate (ZnCO3) and hydrochloric acid (HCl).

The balanced equation for the reaction is as follows:

ZnCO3 + 2HCl → ZnCl2 + H2O + CO2

From the equation, we can determine that 1 mole of ZnCO3 reacts with 2 moles of HCl to produce 1 mole of ZnCl2.

First, we need to calculate the number of moles of ZnCO3 present in the given mass (12.5g). The molar mass of ZnCO3 is determined by adding the atomic masses of each element:
Zn: 65.38 g/mol
C: 12.01 g/mol
O: 16.00 g/mol (3 oxygen atoms in ZnCO3)

Molar mass of ZnCO3 = (65.38 + 12.01 + (16.00 x 3)) g/mol ≈ 125.38 g/mol

To calculate the number of moles:
Number of moles = Mass / Molar mass
Number of moles of ZnCO3 = 12.5 g / 125.38 g/mol

Now, we can use the stoichiometry of the balanced equation to find the moles of ZnCl2 formed. As per the balanced equation, the ratio of ZnCO3 to ZnCl2 is 1:1.

Number of moles of ZnCl2 = Number of moles of ZnCO3

Finally, we can calculate the mass of ZnCl2 formed using the molar mass of ZnCl2, which is 136.286 g/mol:

Mass of ZnCl2 = Number of moles of ZnCl2 x Molar mass of ZnCl2

By substituting the values, we can calculate the mass of zinc chloride that would be obtained.

12.5