Ba2+(aq) + Fe(s) → Ba(s) + Fe3+(aq)

What are the balanced half-reactions for this equation?

Well, this reaction seems like quite a balancing act! Let's break it down into half-reactions and see what we've got:

Half-reaction 1: Ba2+(aq) + 2e- → Ba(s)
Here we have Ba2+ gaining two electrons to become good ol' Barium (Ba) in solid form.

Half-reaction 2: Fe(s) → Fe3+(aq) + 3e-
In this half-reaction, our Fe (iron) loses three electrons and transforms into Fe3+ in aqueous form.

So, with these half-reactions, the overall equation is in balance, just like a well-trained circus performer! Keep those atoms flying high!

To determine the balanced half-reactions, we need to separate the given chemical equation into oxidation and reduction half-reactions.

1. Oxidation Half-Reaction:
In this reaction, Fe is being oxidized from its elemental state (Fe(s)) to Fe3+ ions (Fe3+(aq)). To balance the charges, we need to add 3e- to the reactant side.

Fe(s) → Fe3+(aq) + 3e-

2. Reduction Half-Reaction:
In this reaction, Ba2+ ions (Ba2+(aq)) are being reduced to elemental Barium (Ba(s)). To balance the charges, we don't need to add any electrons (e-) since the Ba2+ ion already carries a 2+ charge.

Ba2+(aq) → Ba(s)

Therefore, the balanced half-reactions are:
Oxidation Half-Reaction: Fe(s) → Fe3+(aq) + 3e-
Reduction Half-Reaction: Ba2+(aq) → Ba(s)

To determine the balanced half-reactions for the given equation:

1. Write the overall balanced equation:
Ba2+(aq) + Fe(s) → Ba(s) + Fe3+(aq)

2. Identify the oxidation and reduction half-reactions.

In this case, Ba2+ is being reduced to Ba(s), so the reduction half-reaction is:
Ba2+(aq) + 2e- → Ba(s)

On the other hand, Fe(s) is being oxidized to Fe3+, so the oxidation half-reaction is:
Fe(s) → Fe3+(aq) + 3e-

Note that the number of electrons in each half-reaction is determined by balancing the charges on both sides of the equation.

Therefore, the balanced half-reactions are:
Oxidation: Fe(s) → Fe3+(aq) + 3e-
Reduction: Ba2+(aq) + 2e- → Ba(s)

Ba2+(aq) + Fe(s) → Ba(s) + Fe3+(aq)

Ba^2+(aq) + 2e ==> Ba(s)
Fe(s) ==> Fe^3+(aq) + 3e

A bunch of redox equations. Do you know the rules? They are easy to follow and it always comes through. There are links that show you how to do this.