How many grams of NaCl would be formed from 100 grams of Na2CO3 in the following reaction?
Na2CO3 + 2 HCl → 2 NaCl + CO2 + H2O
Na2CO3 + 2 HCl → 2 NaCl + CO2 + H2O
mols Na2CO3 = grams/molar mass = 100/106 = approx 0.9 but that's an estimate.
From the equation 1 mol Na2CO3 will produce 2 mols NaCl; therefore you will get approx 2*0.9 = estimated 1.8 mols NaCl
Redo the calculations and convert mols NaCl to grams this way. grams NaCl = mnols NaCl x molar mass NaCl = ?
Post your work if you run into trouble.
1
Well, it looks like you're trying to convert Na2CO3 to NaCl. The molar mass of Na2CO3 is approximately 106 grams/mole, and the molar mass of NaCl is approximately 58.5 grams/mole.
Now, the balanced equation tells us that for every 1 mole of Na2CO3, we get 2 moles of NaCl.
So, let's do some math. We have 100 grams of Na2CO3, which is approximately 0.94 moles. Since the ratio of Na2CO3 to NaCl is 1:2, we'll double that moles to get 1.88 moles of NaCl.
Finally, we can use the molar mass of NaCl to convert moles to grams. Multiplying 1.88 moles by 58.5 grams/mole gives us approximately 110 grams of NaCl.
So, approximately 110 grams of NaCl would be formed. Now, aren't you glad chemistry is not as complicated as relationships?
To find the number of grams of NaCl formed, we need to use the stoichiometry of the reaction, which is the balanced chemical equation.
The balanced chemical equation is:
Na2CO3 + 2 HCl → 2 NaCl + CO2 + H2O
From the equation, we can see that 1 mole of Na2CO3 reacts with 2 moles of HCl to form 2 moles of NaCl.
First, we need to convert the mass of Na2CO3 to moles. To do this, we divide the given mass of Na2CO3 by its molar mass.
The molar mass of Na2CO3 is calculated as follows:
Na: 2(22.99 g/mol) = 45.98 g/mol
C: 1(12.01 g/mol) = 12.01 g/mol
O: 3(16.00 g/mol) = 48.00 g/mol
Adding up these values, we get:
molar mass of Na2CO3 = 45.98 g/mol + 12.01 g/mol + 48.00 g/mol = 105.99 g/mol
Now, we can calculate the number of moles of Na2CO3 by dividing the given mass by the molar mass:
moles of Na2CO3 = 100 g / 105.99 g/mol
Next, we use the stoichiometry of the reaction to find the moles of NaCl formed. From the balanced chemical equation, we know that 2 moles of NaCl are formed for every 1 mole of Na2CO3.
Therefore, the moles of NaCl formed = (moles of Na2CO3) × 2
Finally, we convert the moles of NaCl formed into grams by multiplying by the molar mass of NaCl. The molar mass of NaCl is the sum of the atomic masses of sodium (Na) and chlorine (Cl):
molar mass of NaCl = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol
grams of NaCl formed = (moles of NaCl formed) × (molar mass of NaCl)