Balance and write the net ionic equation for the precipitation reaction below

K2S+Ni(No3)_KNo3+NiS

I have corrected and balanced the molecular equation as follows:

K2S(aq) + Ni(NO3)2(aq) ==> 2KNO3(aq) + NiS(s)
S^2-(aq) + Ni^2+(aq) ==> NiS(s)

What is the role

To balance and write the net ionic equation for the precipitation reaction between K2S (Potassium sulfide) and Ni(NO3)2 (Nickel(II) nitrate), follow these steps:

Step 1: Write the balanced molecular equation:
K2S + Ni(NO3)2 -> 2KNO3 + NiS

Step 2: Split the equation into ions:
2K+ (aq) + S2- (aq) + Ni2+ (aq) + 2NO3- (aq) -> 2K+ (aq) + 2NO3- (aq) + NiS (s)

Step 3: Cancel out the spectator ions (ions that are present on both sides of the equation without undergoing any changes):
2K+ (aq) + S2- (aq) + Ni2+ (aq) + 2NO3- (aq) -> NiS (s)

The net ionic equation for the precipitation reaction is:
S2- (aq) + Ni2+ (aq) -> NiS (s)

To balance and write the net ionic equation for the precipitation reaction, we need to follow a few steps:

Step 1: Write the balanced overall equation:
K2S + Ni(NO3)2 -> 2 KNO3 + NiS

Step 2: Identify the soluble and insoluble compounds:
In this case, K2S is soluble in water, while NiS is insoluble in water.

Step 3: Write the ionic equation:
2 K+ (aq) + S2- (aq) + Ni2+ (aq) + 2 NO3- (aq) -> 2 K+ (aq) + 2 NO3- (aq) + NiS (s)

Step 4: Write the net ionic equation:
The net ionic equation is obtained by removing the spectator ions (ions that appear in the reaction on both sides unchanged). In this case, the K+ and NO3- ions are spectators and thus canceled out:
S2- (aq) + Ni2+ (aq) -> NiS (s)

So, the net ionic equation for the precipitation reaction is S2- (aq) + Ni2+ (aq) -> NiS (s).