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Three designs are proposed for an engine that is to operate between 500 and 300 K. Design A is claimed to produce 750 J of work per kilojoule of heat input, B is claimed to produce 500 J, and C is claimed to produce 250J. Which design would you choose?

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3 answers
  1. efficiency=(500-300)/300=.67
    work output= 1000*eff=670 J
    so the first design A is baloney
    so go with design B would be my choice.

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    👤
    bobpursley
  2. what formula did u use?

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  3. Greetings!

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    Graphic Designer
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