Calculate the mass of cacl2 formed when 5 moles of chlorine reacts with calcium metal
Mass of mol of Cl2 = 2 * 35.5 = about 71 grams
Mass of mol of Ca = about 40 grams
Ca + Cl2 --> CaCl2
so
5 Ca + 5 Cl2 --> 5 CaCl2
Mass of one Mol of CaCl2 = 40 + 71 = 111 grams/ mol
so 5 * 111 = ?
555g
555g
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To calculate the mass of CaCl2 formed when 5 moles of chlorine (Cl2) reacts with calcium (Ca) metal, you need to know the balanced chemical equation for the reaction. The balanced equation for the reaction between chlorine and calcium is:
Ca + Cl2 -> CaCl2
From the balanced equation, we can see that 1 mole of calcium reacts with 1 mole of chlorine to produce 1 mole of calcium chloride (CaCl2). Therefore, 5 moles of chlorine will react with 5 moles of calcium.
Next, you need to determine the molar mass of CaCl2, which is calculated by adding up the atomic masses of all the elements in the compound.
The molar mass of calcium (Ca) is 40.08 grams/mol.
The molar mass of chlorine (Cl) is 35.45 grams/mol.
The molar mass of CaCl2 is:
(1 x molar mass of Ca) + (2 x molar mass of Cl)
= (1 x 40.08) + (2 x 35.45)
= 40.08 + 70.90
= 110.98 grams/mol
Finally, to calculate the mass of CaCl2 formed, you can use the formula:
Mass = moles x molar mass
Mass of CaCl2 = 5 moles x 110.98 grams/mol
= 554.9 grams
Therefore, the mass of CaCl2 formed when 5 moles of chlorine react with calcium metal is 554.9 grams.