On a sunday afternoon, 11 children and 5 adults visit the culver city museum of math oddities at a total admission price of $158.00. Adult tickets cost $6.00 more than children tickets. What is the price of an adult ticket?
Let's set up a system of equations to solve this problem step-by-step.
Let's represent the cost of a child ticket as c and the cost of an adult ticket as a.
From the problem, we know that there are 11 children and 5 adults, and the total admission price is $158.00. Hence, we can set up the equation:
11c + 5a = 158 (Equation 1)
We also know that the cost of an adult ticket is $6.00 more than the cost of a child ticket. So we can set up the equation:
a = c + 6 (Equation 2)
Now we can substitute Equation 2 into Equation 1 to solve for the value of c.
11c + 5(c + 6) = 158
Simplifying the equation:
11c + 5c + 30 = 158
Combining like terms:
16c + 30 = 158
Subtracting 30 from both sides:
16c = 128
Dividing both sides by 16:
c = 8
Now that we know the cost of a child ticket (c = 8), we can substitute it back into Equation 2 to find the cost of an adult ticket (a).
a = 8 + 6
a = 14
Therefore, the price of an adult ticket is $14.00.
To find the price of an adult ticket, we need to set up a system of equations based on the given information. Let's denote the price of a child ticket as "x" (in dollars) and the price of an adult ticket as "x + 6" (since the adult tickets cost $6 more).
We are told that there are a total of 11 children and 5 adults, and the total admission price is $158.00. We can use this information to set up the following equation to represent the total admission price:
11x + 5(x + 6) = 158
Now, we can solve this equation to find the value of "x," which represents the price of a child ticket.
kid's ticket ---- $x
adult's ticket ---- $ x+6
11x + 5(x+6) = 158
Solve for x and all shall be revealed.