![Generate a clean, informative image embodying a scientific concept. It should display a visual representation of the equation '𝐴 = 2.31[𝐶] + 0.002'. Show a graph with absorbance plotted on the y-axis and concentration on the x-axis, indicating a linear regression line. Visualize an unknown point on the line symbolizing an unknown concentration with an absorbance of 0.124 without any numerical values or text.](/images/questions/1823683/1024x1024.png)
The regression line from a plot of absorbance vs. concentration yields: 𝐴 = 2.31[𝐶] + 0.002. If the absorbance of an unknown is measured to be 0.124, what is the concentration of the analyte [𝐶]?
A = 2.31C + 0.002
0.123 = 2.31C + 0.002
(0.123-0.002)/2.31 = C
You solve it.
Thankyouuu.
Well, if we plug in the given absorbance value of 0.124 into the equation, we get:
0.124 = 2.31[C] + 0.002
Now let me calculate... I'm just crunching some numbers here... *beep boop beep*
Ah, the concentration of the analyte [C] turns out to be approximately 0.052 M. So, it looks like we've cracked the case!
To find the concentration of the analyte [𝐶], we can use the equation provided for the regression line:
𝐴 = 2.31[𝐶] + 0.002
We are given that the absorbance of the unknown is 0.124. We can substitute this value into the equation to solve for [𝐶]:
0.124 = 2.31[𝐶] + 0.002
Now, let's isolate the variable [𝐶]:
2.31[𝐶] = 0.124 - 0.002
2.31[𝐶] = 0.122
Divide both sides of the equation by 2.31 to solve for [𝐶]:
[𝐶] = 0.122 / 2.31
Calculating the result:
[𝐶] ≈ 0.0529
Therefore, the concentration of the analyte [𝐶] is approximately 0.0529.
To find the concentration of the analyte [𝐶] given the absorbance value, we can use the equation of the regression line:
𝐴 = 2.31[𝐶] + 0.002
We substitute the given absorbance value (0.124) into the equation:
0.124 = 2.31[𝐶] + 0.002
Now, we can isolate the concentration term [𝐶]. First, we subtract 0.002 from both sides of the equation:
0.124 - 0.002 = 2.31[𝐶]
0.122 = 2.31[𝐶]
To solve for [𝐶], we divide both sides of the equation by 2.31:
𝐶 = 0.122 / 2.31
𝐶 ≈ 0.0529
Therefore, the concentration of the analyte [𝐶] is approximately 0.0529.