20cm^3 of sodium carbonate solution was reacted completely with 25cm^3 of 0.8 M HCL according to the equation. Na2CO3+2HCL-2NaCl+CO2+H2O.Calculate the concentration of the Na2CO3 in grams per litre

Na2CO3 + 2HCL ==> 2NaCl + CO2 + H2O.

mols HCl = M x L = 0.8 x 0.025 = 0.02
mols Na2CO3 must 1/2 that = 0.01
grams Na2CO3 = mols x molar mass = 0.01 x 106 = 1.06
1.06 g/20 mL = ?g/L

Well, let me put on my chemistry clown wig and entertain you with an answer!

To calculate the concentration of Na2CO3 in grams per liter, we'll start by finding the number of moles of Na2CO3 using the given volume and molarity of HCl.

First, let's convert the volume of HCl to liters:
25 cm^3 = 25/1000 = 0.025 L

Now, using the balanced equation, we can see that each mole of Na2CO3 reacts with 2 moles of HCl. Since the molarity of HCl is 0.8 M, it means that 0.8 moles of HCl reacts with 1 liter of HCl solution.

Therefore, the number of moles of HCl used in the reaction is:
0.8 M x 0.025 L = 0.02 moles

Since the mole ratio between Na2CO3 and HCl is 1:2, we can conclude that the number of moles of Na2CO3 used in the reaction is also 0.02 moles.

Now, we know the number of moles of Na2CO3 is 0.02 moles in a total volume of 20 cm^3. To find the concentration in grams per liter, we need to convert the volume to liters.

20 cm^3 = 20/1000 = 0.02 L

Finally, to calculate the concentration of Na2CO3 in grams per liter, we divide the number of moles by the volume in liters:

0.02 moles / 0.02 L = 1 mole/L

Therefore, the concentration of Na2CO3 in grams per liter is 1 mole/L.

I hope my clown chemistry routine brought a smile to your face!

To calculate the concentration of Na2CO3 in grams per liter, you need to determine the amount of Na2CO3 in grams and then convert it to liters.

1. Calculate the number of moles of HCL used:
First, convert the volume of HCL to liters:
25 cm^3 = 25 / 1000 = 0.025 L

Next, use the formula: Moles = Concentration × Volume
Moles of HCL = 0.8 M × 0.025 L = 0.02 moles

Since the mole ratio between HCL and Na2CO3 is 2:1, the number of moles of Na2CO3 used is also 0.02 moles.

2. Convert moles of Na2CO3 to grams:
The molar mass of Na2CO3 is:
2(Na) + (C) + 3(O) = (2 × 22.99 g/mol) + 12.01 g/mol + 3 × 16 g/mol = 105.99 g/mol

Mass of Na2CO3 = Moles × Molar mass
Mass of Na2CO3 = 0.02 moles × 105.99 g/mol ≈ 2.12 g

3. Convert grams to liters:
The given volume is 20 cm^3, which is equal to 20 / 1000 = 0.02 L.

Concentration of Na2CO3 in grams per liter:
Concentration = Mass / Volume
Concentration of Na2CO3 = 2.12 g / 0.02 L = 106 g/L

Therefore, the concentration of Na2CO3 in grams per liter is 106 g/L.

To calculate the concentration of Na2CO3 in grams per liter, we need to determine the amount of Na2CO3 in moles and then convert it to grams.

Step 1: Calculate the number of moles of HCl used in the reaction.
Given:
Volume of HCl = 25 cm^3
Molarity of HCl = 0.8 M

Using the formula: moles = volume (in liters) x molarity
Moles of HCl = 25 cm^3 x (1 liter/1000 cm^3) x 0.8 M
Moles of HCl = 0.02 moles

Step 2: Determine the stoichiometric ratio between Na2CO3 and HCl from the balanced equation.
From the balanced equation: Na2CO3 + 2HCl -> 2NaCl + CO2 + H2O
The stoichiometric ratio between Na2CO3 and HCl is 1:2.

Step 3: Use the stoichiometric ratio to calculate the moles of Na2CO3.
Since the mole ratio is 1:2, the moles of Na2CO3 will be half of the moles of HCl used.
Moles of Na2CO3 = 0.02 moles/2
Moles of Na2CO3 = 0.01 moles

Step 4: Convert moles of Na2CO3 to grams.
Given:
Volume of Na2CO3 solution = 20 cm^3 = 20 ml
Density of Na2CO3 solution = Let's assume it is 1 g/ml (this may vary)

Since the density is 1 g/ml, the mass of 20 ml of Na2CO3 solution will be 20 grams.

To calculate the concentration in grams per liter, we can directly use the mass of the given volume (20 ml), which is equivalent to 20 grams.

Therefore, the concentration of Na2CO3 in grams per liter = 20 g/L.

Note: It is important to consider the actual density of the Na2CO3 solution (given in the question or determined experimentally) to obtain an accurate concentration value.