Calculate the amount of heat released when 100 g of water at 0°C
turns into ice at 0°C ( Phase change: Freezing)
the heat of fusion (water-to-ice , ice-to-water) is 334 Joules per gram
Well, let's break the ice, shall we? When 100 g of water wants to become ice at 0°C, it needs a little bit of heat to make the transformation. This process is called freezing, and it releases a specific amount of heat energy.
The heat released during freezing, also known as the heat of fusion, for water is approximately 334 joules per gram. So, let's do some math.
100 grams of water multiplied by 334 joules per gram equals 33,400 joules of heat released during this freezing process.
That's a lot of heat! So, if you ever need to freeze some water, expect it to be quite a chilling experience!
To calculate the amount of heat released during the phase change from liquid water to solid ice, we need to use the equation:
Q = m * ΔHf,
where:
Q is the amount of heat released (in Joules),
m is the mass of the substance (in grams), and
ΔHf is the enthalpy of fusion (heat of fusion) of the substance (in J/g).
For water, the enthalpy of fusion (ΔHf) is 334 J/g.
Plugging in the values:
Q = 100 g * 334 J/g
Q = 33,400 J
Therefore, the amount of heat released when 100 g of water at 0°C turns into ice at 0°C is 33,400 Joules.
To calculate the amount of heat released when water freezes, we need to use the specific heat and heat of fusion of water. Here are the steps to calculate it:
1. Calculate the heat required to raise the temperature of 100 g of water from 0°C to its freezing point:
- The specific heat capacity of water is 4.18 J/g°C. Therefore, the heat required would be:
Heat1 = mass * specific heat * temperature change
= 100 g * 4.18 J/g°C * (0°C - 0°C)
= 0 J
2. Calculate the heat released during the phase change (freezing) of water at 0°C:
- The heat of fusion for water is 334 J/g. Therefore, the heat released would be:
Heat2 = mass * heat of fusion
= 100 g * 334 J/g
= 33400 J
3. Calculate the total heat released:
Total heat released = Heat1 + Heat2
= 0 J + 33400 J
= 33400 J
Therefore, the amount of heat released when 100 g of water at 0°C turns into ice at 0°C is 33400 J.