Ask questions and get helpful answers.

A ball is thrown into the air with an upward velocity of 48 /. Its height ℎ in feet after seconds is given by the function ℎ = −162 + 48 + 9. How long does it take the ball to reach is the maximum height? What is the ball’s maximum height? Round to the nearest hundredth, if necessary.

please help

  1. 👍
  2. 👎
  3. 👁
  4. ℹ️
  5. 🚩
4 answers
  1. You need to proofread your post. Clearly you meant
    h = −16t^2 + 48t + 9
    it reaches its maximum height when v=0
    v = 48-32t
    Now you have t, so plug it in to find h

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
    👤
    oobleck
  2. thank you so much

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  3. V = Vo + g*T = 0
    48 + (-32)T = 0
    T = 1.5 s.

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  4. its 4

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩

Answer this Question

Related Questions

Still need help?

You can ask a new question or browse existing questions.