a 15kg wagon Is pulled to the right with a force of 45 newtons. The wagon accelerates at 2 m/s^2 what is the magnitude of the frictional force acting on the wagon

F = m a

45 - Ff = 15 * 2
Ff = 45 - 30 Newtons = 15 Newtons

Well, well, well, looks like the wagon is having a bit of a struggle, huh? Okay, let's figure this out.

Firstly, we need to calculate the net force acting on the wagon. The net force is the sum of the applied force and the frictional force. In this case, the applied force is 45 newtons to the right.

We can use Newton's second law (F = ma) to calculate the net force:

Net force = (mass) * (acceleration)
Net force = 15 kg * 2 m/s^2
Net force = 30 N

Now, remember that the net force is the sum of the applied force and the frictional force. Since the net force is to the right, and the applied force is also to the right, we can determine that the frictional force is to the left.

So, the magnitude of the frictional force can be calculated by subtracting the applied force from the net force:

Frictional force = Net force - Applied force
Frictional force = 30 N - 45 N
Frictional force = -15 N

Ta-da! The magnitude of the frictional force acting on the wagon is 15 newtons. But remember, since it's negative, it means the frictional force opposes the motion and acts in the opposite direction of the applied force.

To find the magnitude of the frictional force acting on the wagon, we can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration (F = m * a).

Given:
Mass of wagon (m) = 15 kg
Force exerted (F) = 45 N
Acceleration (a) = 2 m/s^2

Using Newton's second law, we can rearrange the formula to find the frictional force (F_friction):

F_friction = F - m * a

Substituting the given values:

F_friction = 45 N - 15 kg * 2 m/s^2

Calculating:

F_friction = 45 N - 30 N

F_friction = 15 N

Therefore, the magnitude of the frictional force acting on the wagon is 15 Newtons.

To find the magnitude of the frictional force acting on the wagon, we need to use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration.

First, let's calculate the net force acting on the wagon. The force pulling the wagon to the right is 45 newtons, and the mass of the wagon is 15 kg. So, the net force is:

Net force = mass × acceleration
= 15 kg × 2 m/s^2
= 30 N

Now, the frictional force acts in the opposite direction to the motion of the wagon. So, the frictional force would be equal in magnitude but opposite in direction to the net force. Therefore, the magnitude of the frictional force is 30 newtons.

Hence, the magnitude of the frictional force acting on the wagon is 30 newtons.