The ratio of boys to girls in a class is 7:4. If there are 9 more boys than girls how many children are in the class?

this makes no sense wtf i dont get maths

Well, if we assume that the number of boys is 7x and the number of girls is 4x, we can set up an equation: 7x - 4x = 9. Solving for x, we get x = 9. So the number of boys is 7 * 9 = 63, and the number of girls is 4 * 9 = 36. Combined, the class has 63 + 36 = 99 children. It's like a whole circus in there!

To solve this problem, we need to use the given information to set up an equation.

Let's assume the number of boys is represented by the variable "b" and the number of girls is represented by the variable "g". We know that the ratio of boys to girls is 7:4, which means for every 7 boys, there are 4 girls. So we can write the equation:

b/g = 7/4

We are also given that there are 9 more boys than girls, which can be expressed as:

b = g + 9

Now we can substitute the value of "b" from the second equation into the first equation:

(g + 9)/g = 7/4

To solve this equation, we can cross-multiply:

4(g + 9) = 7g

Expanding the left side of the equation:

4g + 36 = 7g

Subtracting 4g from both sides:

36 = 3g

Dividing both sides by 3:

g = 12

Now that we have the value for "g", we can substitute it back into the equation b = g + 9 to find the value of "b":

b = 12 + 9
b = 21

Therefore, there are a total of 12 + 21 = 33 children in the class.

If there are 7x boys and 4x girls, then

7x = 4x+9
solve for x, and then there are 11x children.

X girls and x+9 boys.

(x+9)/x = 7/4
4x+36 = 7x
X = 12 girls.
x+9 = 12+9 = 21 boys.
Total = 12+21 =