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The heights of boys at a particular age follow a normal distribution with mean 150.3 and standard deviation 5cm. Find the probability that the height of a boy picked at random from the age group is i.more than 10 cm from the mean height.

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  1. 95.4% of a normally distributed population lies within two s.d. of the mean

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  2. Z = (score-mean)/SD = (score-105.3)/5

    Since you don't indicate the direction of deviation, the score could be 140.3 or 160.3. If you don't want to use the equation, the scores are ± 2Z.

    Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability for the Z scores.

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