Water is added to 200 cm3 of a 2.0 M solution of CaCl2 to increase the volume of the solution to 400 cm3. What is the new concentration?
1.0
To find the new concentration of the solution, we need to use the formula:
C1V1 = C2V2
where:
C1 = initial concentration of the solution (2.0 M)
V1 = initial volume of the solution (200 cm3)
C2 = final concentration of the solution (unknown)
V2 = final volume of the solution (400 cm3)
We can rearrange the formula to solve for C2:
C2 = (C1V1) / V2
Let's plug in the values:
C2 = (2.0 M * 200 cm3) / 400 cm3
C2 = 1.0 M
Therefore, the new concentration of the solution is 1.0 M.
To find the new concentration of the solution after water is added, we need to use the equation:
M1 × V1 = M2 × V2
Where:
M1 = initial concentration of the solution (2.0 M)
V1 = initial volume of the solution (200 cm^3)
M2 = new concentration of the solution (to be determined)
V2 = new volume of the solution (400 cm^3)
We can rearrange the equation to solve for M2:
M2 = (M1 × V1) / V2
Plugging in the values:
M2 = (2.0 M × 200 cm^3) / 400 cm^3
Now, let's simplify the expression:
M2 = (2.0 × 200) / 400
M2 = 400 / 400
M2 = 1.0 M
Therefore, the new concentration of the solution is 1.0 M.
cc1 x M1 = cc2 x M2
200 x 2 M = 400 x M2
M2 = ?