The intersection of roads M and N create a 41.4° angle. What are the complementary and supplementary angles of this intersection?
A better way to find why it's A is because a complementary angle equals 90 so it would be 90-41.4=48.6. I hope this helps you better understand the problem
It would be a
A:
The complementary angle is 48.6° and the supplementary angle is 138.6°.
B:
The supplementary angle is 79.8° and the supplementary angle is 97.2°.
C:
The complementary angle is 138.6° and the supplementary angle is 48.6°.
D: The complementary angle is 97.2° and the supplementary angle is 79.8°.
thank you Random that helped :)
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To find the complementary angle of the intersection of roads M and N, subtract the given angle from 90°.
Complementary angle = 90° - 41.4° = 48.6°
To find the supplementary angle of the intersection of roads M and N, subtract the given angle from 180°.
Supplementary angle = 180° - 41.4° = 138.6°
So, the complementary angle is 48.6° and the supplementary angle is 138.6°.