A 4g of sugar cube sucrose (C12 H22 O11) is dissolved in a 350ml teacup of 80 degree census of water

1: What will be the molarity of the sugar
2:What is the percentage composition by mass of the sugar

I assume you meant 80 Celsius.

M = mols/L and mols = grams/molar mass
mols C12H22O11 = 4/342 = estimated 0.013
mols/L = estimated 0.013/0.350 = ?

%by mass = grams sugar/100 g solution
(4/354)*100 = ?

To find the molarity of the sugar, we need to calculate the number of moles of sugar present in the 4g of sucrose.

1. Calculate the molar mass of sucrose (C12H22O11):
- Carbon (C) has a molar mass of 12.01 g/mol
- Hydrogen (H) has a molar mass of 1.01 g/mol
- Oxygen (O) has a molar mass of 16.00 g/mol

Molar mass of C12H22O11 = (12.01 g/mol x 12) + (1.01 g/mol x 22) + (16.00 g/mol x 11) = 342.34 g/mol

2. Calculate the number of moles using the formula:
Number of moles = mass / molar mass

Number of moles of sucrose = 4g / 342.34 g/mol = 0.01167 mol

3. Calculate the volume in liters:
350 ml = 0.35 liters

4. Calculate the molarity using the formula:
Molarity (M) = moles / volume in liters

Molarity of the sugar solution = 0.01167 mol / 0.35 L = 0.03341 M

Therefore, the molarity of the sugar is 0.03341 M.

To find the percentage composition by mass of the sugar, we need to calculate the mass of each element in the sugar and divide it by the total mass of the sugar.

1. Calculate the mass of each element in sucrose:
- Carbon (C): 12.01 g/mol x 12 = 144.12 g
- Hydrogen (H): 1.01 g/mol x 22 = 22.22 g
- Oxygen (O): 16.00 g/mol x 11 = 176.00 g

2. Calculate the total mass of the sugar:
Total mass = mass of C + mass of H + mass of O = 144.12 g + 22.22 g + 176.00 g = 342.34 g

3. Calculate the percentage composition by mass of each element using the formula:
Percentage composition = (mass of element / total mass) x 100

Percentage composition of Carbon (C) = (144.12 g / 342.34 g) x 100 = 42.11%
Percentage composition of Hydrogen (H) = (22.22 g / 342.34 g) x 100 = 6.48%
Percentage composition of Oxygen (O) = (176.00 g / 342.34 g) x 100 = 51.41%

Therefore, the percentage composition by mass of the sugar is approximately:
C: 42.11%
H: 6.48%
O: 51.41%

To find the molarity of the sugar solution, you need to calculate the number of moles of sugar (sucrose) in the given amount of sugar.

1. Calculate the number of moles of sugar (C12H22O11):
To calculate the number of moles, you can use the formula:

moles = mass / molar mass

The molar mass of sucrose (C12H22O11) is calculated by adding up the atomic masses of all the atoms in one molecule of sucrose.

Molar mass of C12H22O11 = (12 * 12.01 g/mol) + (22 * 1.01 g/mol) + (11 * 16.00 g/mol)
= 144.12 g/mol + 22.22 g/mol + 176.00 g/mol
= 342.34 g/mol

Now, substitute the given mass (4g) into the formula:

moles = 4g / 342.34 g/mol
≈ 0.01167 mol

2. Calculate the molarity of the sugar solution:
Molarity is defined as the number of moles of solute per liter of solution (moles/L).

Molarity (M) = moles / volume in liters

Given that the volume of the solution is 350 mL, convert it to liters by dividing by 1000:

Volume in liters = 350 mL / 1000
= 0.35 L

Now, substitute the values into the formula:

Molarity (M) = 0.01167 mol / 0.35 L
≈ 0.033 M

Therefore, the molarity of the sugar solution is approximately 0.033 M.

Now, let's move on to finding the percentage composition by mass of the sugar (sucrose).

To find the percentage composition by mass, you need to calculate the mass of each component in the sugar (C, H, and O) and divide it by the total mass of the sugar (sucrose) and multiply by 100.

1. Calculate the mass of carbon (C):
To find the mass of carbon (C), multiply the number of moles of carbon by its molar mass.

Mass of C = moles of C * molar mass of C
= 12 * 12.01 g/mol
= 144.12 g/mol

2. Calculate the mass of hydrogen (H):
To calculate the mass of hydrogen (H), multiply the number of moles of hydrogen by its molar mass.

Mass of H = moles of H * molar mass of H
= 22 * 1.01 g/mol
= 22.22 g/mol

3. Calculate the mass of oxygen (O):
To calculate the mass of oxygen (O), multiply the number of moles of oxygen by its molar mass.

Mass of O = moles of O * molar mass of O
= 11 * 16.00 g/mol
= 176.00 g/mol

4. Calculate the total mass of the sugar (sucrose):
The total mass of the sugar is calculated by adding the masses of all the components.

Total mass of sugar = mass of C + mass of H + mass of O
= 144.12 g + 22.22 g + 176.00 g
= 342.34 g

5. Calculate the percentage composition by mass of the sugar:
To find the percentage composition by mass, divide the mass of each component by the total mass and multiply by 100.

Percentage composition of C = (mass of C / total mass) * 100
= (144.12 g / 342.34 g) * 100
≈ 42.10%

Percentage composition of H = (mass of H / total mass) * 100
= (22.22 g / 342.34 g) * 100
≈ 6.49%

Percentage composition of O = (mass of O / total mass) * 100
= (176.00 g / 342.34 g) * 100
≈ 51.41%

Therefore, the percentage composition by mass of the sugar (sucrose) is approximately:
Carbon (C): 42.10%
Hydrogen (H): 6.49%
Oxygen (O): 51.41%

molar mass of sucrose ... 342 g

molarity = moles per liter = (4 / 342) / .35

% mass = [4 g / (4 g + 350 g)] * 100%