1.which is most likely to be part of an ionic bond?

A. an atom with no valence electrons
B. an atom with one valence electron
C. an atom with two valence electrons
D. an atom with three valence electrons
My answer is C.an atom with two......

Elements with 1, 2, or 3 valence electrons can form ionic bonds. I think the secret phrase here is "most likely" so I would go with B. All elements with one valence electron (except H and that CAN form a ionic bond as hydrides) form an ionic bond.

okay for the next Question

3.) what is true about the element francium (Fr, atomic number 87)? choose all that apply.
A. it has seven valence electrons
B. it is likely to form ionic bonds
C. it is a nonmetal
D. it is in period seven
E. it is a metal

If you can pick only one, yes, I would go with B.

For the next question, you should know all about this from the periodic table.
A. It is in group I; therefore it has 1 valence electron.
B. From the first question you know it is likely to form an ionic bond.
C. It is in the left most part of the periodic table which houses metals.
D. Look at the periodic table and count the period it is in.
E. See my response to C.

There are three correct answers listed.

For the original question, it is 1 valance electron.

To determine which atom is most likely to be part of an ionic bond, we need to understand the concept of valence electrons. Valence electrons are the electrons located in the outermost shell of an atom. These electrons are responsible for the chemical behavior of an element.

Ionic bonds occur between atoms with a significant difference in electronegativity. Electronegativity refers to an atom's ability to attract electrons. In an ionic bond, one atom with a low electronegativity will transfer electrons to an atom with a high electronegativity.

In this case, the correct answer is C. an atom with two valence electrons. This is because an atom with two valence electrons is more likely to transfer those two electrons to another atom with a higher electronegativity. This transfer creates an electrostatic attraction between the two oppositely charged ions, resulting in an ionic bond.

To determine the number of valence electrons an atom has, you can refer to the periodic table. The periodic table is organized in groups and periods. The group number indicates the number of valence electrons in that specific group of elements.

For example, group 1 elements (such as sodium and potassium) have one valence electron, group 2 elements (such as magnesium and calcium) have two valence electrons, and so on.

Therefore, an atom with two valence electrons is most likely to be part of an ionic bond.

so the answer is B