What is the equation of a circle with its center at (10,−4) and a radius of 2?
(x−10)2+(y+4)2=4
(x+10)2+(y−4)2=2
(x−10)2+(y+4)2=2
(x+10)2+(y−4)2=4
can someone please help i do not understand
the equation of a circle is (x-h)^2 + (x-k)^2 = r^2,
r = radius
h, k = x and y points of the center
you would plug in the center point coordinates into the circle equation to find your answer
therefore its B) (x+10)2+(y−4)2=2 :)
Sure! I'll be happy to help explain how to solve this problem.
The equation for a circle with its center at point (h, k) and a radius of r is given by:
(x - h)^2 + (y - k)^2 = r^2.
In our case, the center of the circle is (10, -4), and the radius is 2. Substituting these values into the equation, we get:
(x - 10)^2 + (y + 4)^2 = 2^2.
Simplifying further, we have:
(x - 10)^2 + (y + 4)^2 = 4.
So, the correct equation for the circle with a center at (10, -4) and a radius of 2 is:
(x - 10)^2 + (y + 4)^2 = 4.
Hence, the correct answer is (x - 10)^2 + (y + 4)^2 = 4.