(dy/dx)=X^3/8  1/2x^3.
what is sqrt( 1+(dy/dx)^2 ) and that multiplied by (dy/dx)
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It is sqrt(dy/dx^2 + dy/dx^4)
Is your first dy/dx term x^(3/8) or (x^3)/8 ? Is the second term (1/2)x^2 or 1/(2x^3) ?
It seems to me all you have to do is substitute the dy/dx you already know into whatever you want to calculate. 👍
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drwls
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