Carbon dioxide (CO2) reacts with water (H2O) to form carbonic acid (H2CO3).
Which equation demonstrates the law of conservation of matter for this reaction?
A. 2 CO + H2O —> H2CO3
B. CO2 + H2O —> H2CO3
C. CO2 + 2 H2O —> 2 H2CO3
D. 2 CO2 + 2 H2O —> 4 H2CO3
is it B?
B.CO2 + H2O ---> H2CO3
Yes, B is correct.
Yes, the correct equation that demonstrates the law of conservation of matter for the reaction between carbon dioxide (CO2) and water (H2O) to form carbonic acid (H2CO3) is B. CO2 + H2O —> H2CO3.
To determine which equation demonstrates the law of conservation of matter for this reaction, we need to consider the balanced equation. The law of conservation of matter states that matter cannot be created or destroyed in a chemical reaction, only rearranged. This means that the number and type of atoms should be equal on both sides of the equation.
Let's analyze each option:
A. 2 CO + H2O --> H2CO3
In this equation, there are two carbon monoxide (CO) molecules on the left side but only one carbon atom on the right side. So, this equation does not demonstrate the law of conservation of matter.
B. CO2 + H2O --> H2CO3
This equation has one carbon dioxide (CO2) molecule on the left side and one carbon atom, which is consistent with the law of conservation of matter. The equation correctly balances the reactants and products.
C. CO2 + 2 H2O --> 2 H2CO3
This equation has one carbon dioxide (CO2) molecule on the left side and two carbon atoms on the right side. The equation does not fulfill the law of conservation of matter.
D. 2 CO2 + 2 H2O --> 4 H2CO3
In this equation, there are two carbon dioxide (CO2) molecules on the left side and four carbon atoms on the right side. So, this equation does not satisfy the law of conservation of matter.
Considering the analysis above, the correct equation that demonstrates the law of conservation of matter for this reaction is option B: CO2 + H2O --> H2CO3.