Iron (III) Nitrate reacts with sodium carbonate to form a precipitate.
Be sure to indicate oxidation states and the precipitate.
Skeletal Equation:
Ionic Equation:
NET Ionic Equation:
Balanced Equation:
Spectator Ions:
I got the skeletal equation, but I need help with the Ionic Equation and the NET Ionic Equation. Please help!!
And why didn't you write what you know? I assume those are SOLUTIONS of ferric nitrate and sodium carbonate.
Iron (III) Nitrate reacts with sodium carbonate to form a precipitate.
The molecular equation is as follows: I assume you have that.
Fe(NO3)3(aq) + Na2CO3(aq) ==> Fe2(CO3)3(s) + NaNO3(aq). Balance that.
2Fe(NO3)3(aq) + 3Na2CO3(aq) ==> Fe2(CO3)3(s) + 6NaNO3(aq).
That is the total balanced equation. Now turn that into the total ionic equation.
2Fe^3+(aq) + 6(NO3)-(aq) + 6Na^+ + 3(CO3)^2-(aq) ==> Fe2(CO3)3(s) + 6Na^+ + 6(NO3)^-(aq).
To turn this into the net ionic equation, cancel those ions common to both sides of the equation. Those are Na^+ and (NO3)^-. The net ionic equation is what is left. That is.
2Fe^3+(aq)+ + 3(CO3)^2-(aq) ==> Fe2(CO3)3(s)
Thank you!!
How do we write the spectator ions then?
Sure, I'm here to help! Let's start by writing the skeletal equation:
Skeletal Equation: Fe(NO3)3 + Na2CO3 → Fe(CO3)3 + 3NaNO3
Now let's write the ionic equation by separating the compounds into their respective ions:
Ionic Equation: Fe^3+ (aq) + 3(NO3^-) (aq) + 2Na^+ (aq) + CO3^2- (aq) → Fe(CO3)3 (s) + 3Na^+ (aq) + 3(NO3^-) (aq)
Next, let's write the NET ionic equation by removing the spectator ions. Spectator ions are those that appear on both sides of the equation and do not participate in the reaction:
NET Ionic Equation: Fe^3+ (aq) + 3CO3^2- (aq) → Fe(CO3)3 (s)
In this case, Na^+ and NO3^- are the spectator ions.
Finally, let's balance the equation:
Balanced Equation: 2Fe(NO3)3 + 3Na2CO3 → Fe2(CO3)3 + 6NaNO3
Hope that helps! Let me know if you have any more chemistry conundrums.
To determine the ionic equation and net ionic equation, we first need to write the balanced equation for the reaction.
1. Skeletal Equation:
Fe(NO3)3 + Na2CO3 -> Fe(CO3)3 + NaNO3
2. Balanced Equation:
To balance the equation, we need to make sure that the number of each element is equal on both sides of the equation. Here's the balanced equation:
2 Fe(NO3)3 + 3 Na2CO3 -> Fe2(CO3)3 + 6 NaNO3
Now, we can proceed to write the ionic equation.
3. Ionic Equation:
In the ionic equation, we separate all the soluble ionic compounds into their respective ions. The insoluble compound forms a precipitate. Let's break down each compound:
Fe(NO3)3: 2 Fe3+ + 6 NO3-
Na2CO3: 2 Na+ + CO3^2-
Fe2(CO3)3: 2 Fe3+ + 3 CO3^2-
NaNO3: 2 Na+ + 2 NO3-
Now, let's write the ionic equation by substituting the individual ions:
2 Fe3+ + 6 NO3- + 2 Na+ + CO3^2- -> 2 Fe3+ + 3 CO3^2- + 2 Na+ + 6 NO3-
Please note that the spectator ions (Na+ and NO3-) remain unchanged throughout the reaction and are present on both sides of the equation.
4. NET Ionic Equation:
The net ionic equation includes only the ions that participate in the reaction. We will remove the spectator ions from the ionic equation:
Net Ionic Equation: CO3^2- -> Fe3+ + 3 CO3^2-
In the net ionic equation, the carbonate ion (CO3^2-) reacts with the iron (III) ion (Fe3+) to form the precipitate iron (III) carbonate (Fe2(CO3)3).
Therefore, the precipitate formed in this reaction is iron (III) carbonate (Fe2(CO3)3).