Ask questions and get helpful answers.

An object act upon by two forces 5N and 12N. calculate the resultant Of the two forces if the two forces act perpendicular to each other, if the two forces act at angle 40 degree to each other, if the two forces act at an angle 125 degree to each other

  1. 👍
  2. 👎
  3. 👁
  4. ℹ️
  5. 🚩

7 answers

  1. 5 in x direction, 12 in y direction
    hypotenuse = sqrt (25 +144) = 13 N
    angle above x axis = tan^-1(12/5)

    5 in x dir and 12 at 40 deg up
    x component = 5 + 12 cos 40 = 14.2
    y component = 12 sin 40 = 7.71
    hypotenuse = sqrt ( 14.2^2 + 7.71^2)
    angle above x axis = tan^-1 (7.71/14.2)

    last one the same way

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
    👤
    Damon
  2. An object is acted upon by two forces 5N and 12N. Calculate the resultant of the two forces if the forces act perpendicular to each other.
    Cosine rule:a²=b²+c²-2bc cos A
    r=360-(40+40)
    r=360°-80
    r=280°/2=140°
    Using the cosine rule:
    R²=Z²+Y²-(2ZY) cos r
    R²=5²+12²-(2*5*12) cos140°
    R²=25+144-120*(-0.7660)
    R²=169+91.92
    R²=260.92
    R=√260.92
    R=16.1530
    Using the sine rule
    Sine z/5=sine140/16.1530
    Sine z/5=0.6427/16
    1530
    Cross multiply
    16.1630sin z=5*0.6427
    Divide both sides by the coefficient of sin z
    Sin z=0.1989
    Z=sine^_1 0.1989
    Z=sine^-1 0.1989
    Z=11.5

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  3. a. Fr = 5 + 12i = 13N.[67.4o]. = Resultant force.

    b. Fr = 5 + 12[40o].
    Fr = (5+12*cos40) + (12*sin40)I = 14.2 + 7.71i = 16.2N.[28.5o].

    c. Fr = 5 + 12[125o].
    Fr = (5+12*cos125) + (12*sin125)I
    Fr = -1.88 + 9.83i =

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  4. Thank u

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  5. Thanx

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  6. 12n-5n=7n

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  7. 172&

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩

Answer this Question

Related Questions

Still need help?

You can ask a new question or browse existing questions.