A student placed 10.5g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then carefully added additional water until the 100.- mL mark on the neck of the flask was reached. The flask was then shaken until the solution was uniform. A 20.0-mL sample of this glucose solution was diluted to 0.500 L. How many grams of glucose are in 100mL. of the final solution?
answer in Grams
Well, let's do some math, shall we? We start with 10.5g of glucose in 100mL of solution.
To find out how many grams of glucose are in 1mL of the solution, we divide 10.5g by 100mL. This gives us 0.105g/mL.
Since we want to know how many grams are in 100mL of the final solution, we just multiply 0.105g/mL by 100 mL.
So, the answer is 10.5 grams. Ta-da!
To find the number of grams of glucose in 100 mL of the final solution, we will first calculate the concentration of glucose in the original solution.
1. Calculate the molar mass of glucose (C6H12O6):
- Carbon (C): 12.01 g/mol
- Hydrogen (H): 1.01 g/mol
- Oxygen (O): 16.00 g/mol
Molar mass of C6H12O6 = (6 * 12.01 g/mol) + (12 * 1.01 g/mol) + (6 * 16.00 g/mol)
= 72.06 g/mol + 12.12 g/mol + 96.00 g/mol
= 180.18 g/mol
2. Calculate the number of moles of glucose in the original 10.5 g:
Moles of glucose = Mass of glucose / Molar mass of glucose
= 10.5 g / 180.18 g/mol
≈ 0.0582 mol
3. Calculate the concentration of glucose in the original solution (10.5 g in 100 mL):
Concentration = moles of glucose / volume of solution (in L)
= 0.0582 mol / 0.100 L
= 0.582 mol/L
Next, we will calculate the number of moles of glucose in the final solution.
4. Using the dilution formula (C1V1 = C2V2), we can find the final concentration (C2):
- C1 = initial concentration of glucose (0.582 mol/L)
- V1 = initial volume of glucose solution (20 mL or 0.020 L)
- V2 = final volume of diluted solution (0.500 L)
C2 = (C1 * V1) / V2
= (0.582 mol/L * 0.020 L) / 0.500 L
≈ 0.0233 mol/L
5. Calculate the number of moles of glucose in the final solution:
Moles of glucose = Concentration * Volume of solution (in L)
= 0.0233 mol/L * 0.500 L
= 0.0117 mol
6. Calculate the mass of glucose in the final solution (0.0117 mol):
Mass of glucose = Moles of glucose * Molar mass of glucose
= 0.0117 mol * 180.18 g/mol
≈ 2.11 g
Therefore, there are approximately 2.11 grams of glucose in 100 mL of the final solution.
To find the number of grams of glucose in 100 mL of the final solution, we need to consider the dilution process that took place.
First, the student dissolved 10.5 g of glucose in enough water to fill a 100 mL volumetric flask. This means that the 10.5 g of glucose is already in the 100 mL solution.
Then, the student took a 20.0 mL sample of this glucose solution and diluted it to 0.500 L. To find the concentration of glucose in this diluted solution, we can use the following dilution formula:
C1V1 = C2V2
Where:
C1 = initial concentration (10.5 g/100 mL)
V1 = initial volume (20.0 mL)
C2 = final concentration (unknown)
V2 = final volume (0.500 L)
Rearranging the equation to solve for C2:
C2 = (C1 * V1) / V2
Substituting the values:
C2 = (10.5 g / 100 mL) * (20.0 mL / 0.500 L)
Now we can calculate the concentration of glucose in the diluted solution.
C2 = 0.105 g/mL
Since we diluted a 20.0 mL sample to obtain a final volume of 0.500 L (which is 500 mL), we can determine the number of grams of glucose in 100 mL of the final solution.
grams of glucose in 100 mL = (C2 * 100 mL) / 500 mL
grams of glucose in 100 mL = (0.105 g/mL) * (100 mL / 500 mL)
grams of glucose in 100 mL = 0.021 g
Therefore, there are 0.021 grams of glucose in 100 mL of the final solution.
10.5 g/100 mL = 0.105 g/mL.
You took 20 mL which contains 20 x 0.105 g/mL.
Now you diluted that 20 to 500 so the 500 now contains 20 x 0.105 g/mL = 2.10 g so you now have 2.10/500 mL = 0.00420 g/mL. How much is in 100 mL of that solution?