GCF of 2 natural numbers is 3 and their LCM is 180 if one of the numbers is 45 then find second number
Number property:
The product of the two numbers = (GCF)*(LCM)
So if the 2nd number is x
45x = 3(180)
x = 12
check: 12 and 45
12 = 2*2*3
45 = 3*3*5
So the LCF = 3
So the LCM = 2*2*3*3*5 = 180
the should be .x=12, LCF=3
LCM(x,45)=180 and GCF(x,45)=3 then
Solution 45x=180
45x/45=180/45
X=4 then x*GCF
4*3=12
For any natural numbers A&B,
LCM(A,B)*GCF(A,B) is equal to the product of A&B,so 180*3/45 w/c becomes 540/45 equal to 12