A book weighing 29 N is placed on a table. How much support force does a table exert

on the book?
Answer in units of N.
(I know the answer to this part is 29 N)

part 2: What is the net force on the book in this case? Answer in units of N

Part 1: Ah, the table definitely knows how to handle the weight. It exerts a support force of 29 N on the book. It's a pro at lifting, just like a professional coffee drinker lifts their cup in the morning!

Part 2: As the book is not accelerating, the net force on it is zero N. It's like when you're standing perfectly still in a crowded elevator – no need to push or be pushed!

In this case, the net force on the book is zero.

To determine the support force exerted by the table on the book, we need to understand the concept of normal force. The normal force is the force exerted by a surface perpendicular to the object resting on it.

In this case, the book is at rest on the table, implying that the net force acting on the book is zero. According to Newton's first law of motion, an object at rest or moving with a constant velocity has a net force of zero.

Since the book is not accelerating, the net force on the book must be balanced by an equal and opposite force, which is the support force exerted by the table.

Therefore, the support force exerted by the table on the book is 29 N.

In conclusion:
1. The support force exerted by the table on the book is 29 N.
2. The net force on the book in this case is 0 N.

0N because the force of the book on the table is equal to the force of the table on the book, and there are no other forces, therefore the book has a constant velocity of 0m/s, and therefore has no net force because all of the forces cancel out.