Mora is now 3 times as old as her daughter 5 years ago her age was 10 years more than her daughter age will be 5 years from now .determine Mora's present age.
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Restating your post so it makes sense.
Mora is now 3 times as old as her daughter. 5 years ago her age was 10 years more than her daughter age will be 5 years from now. Determine Mora's present age.
daughter's present age ---- x
Mora's present age = 3x
Mora's age 5 years ago = 3x-5
daughter's age 5 years from now = x+5
3x-5 - (x+5) = 10
take over
Well, it seems like Mora's age is quite puzzling. Let's try to solve this problem with a pinch of humor!
Let's say Mora's daughter is currently X years old. So, 5 years ago, Mora was already three times as old as her daughter, making her "three times the trouble, too."
Ten years from now, Mora's daughter will be X + 15 years old (since 5 years have passed). Mora's age at that time is X * 3 + 10 years older than her daughter's future age.
Here comes the punchline: Since these two statements are connected, we can set up an equation: X * 3 + 10 = X + 15.
Solving this equation with the help of our mathematical circus act, we find that X equals 5.
So, Mora's daughter is currently 5 years old. And applying the multiplication trick, Mora's age is 5 * 3 = 15 years young!
Therefore, Mora's present age is 15 years.
Let's assign variables to the ages of Mora and her daughter.
Let's say Mora's present age is "M" and her daughter's present age is "D".
According to the first part of the problem, "Mora is now 3 times as old as her daughter." This can be expressed as:
M = 3D
According to the second part of the problem, "5 years ago, her age was 10 years more than her daughter's age will be 5 years from now." This can be expressed as:
(M - 5) = (D + 5) + 10
Now, we have two equations:
1) M = 3D
2) (M - 5) = (D + 5) + 10
To solve these equations simultaneously, we can substitute the value of M from equation 1 into equation 2:
(3D - 5) = (D + 5) + 10
Simplifying this equation, we get:
3D - 5 = D + 15
Moving all the D terms to one side and all the constant terms to the other side, we have:
3D - D = 15 + 5
2D = 20
Dividing both sides of the equation by 2, we get:
D = 10
Now, substituting this value of D into equation 1, we can find M:
M = 3 * 10
M = 30
Therefore, Mora's present age is 30.
To determine Mora's present age, we will need to break down the information given step by step.
Let's denote Mora's present age as M and her daughter's present age as D.
1. "Mora is now 3 times as old as her daughter": This can be represented as M = 3D.
2. "Five years ago, Mora's age was 10 years more than her daughter's age will be 5 years from now": Let's consider Mora's age 5 years ago as (M-5) and her daughter's age 5 years from now as (D+5). According to the given information, (M-5) = (D+5) + 10.
Now, using the two equations derived above, we can solve for M.
From equation 1: M = 3D.
Substituting this value of M in equation 2: (3D - 5) = (D + 5) + 10.
Simplifying the equation: 3D - 5 = D + 15.
Moving terms around: 3D - D = 15 + 5.
Combining like terms: 2D = 20.
Dividing both sides by 2: D = 10.
Therefore, Mora's daughter's present age is 10 years. Substituting this value back into equation 1, we find Mora's present age: M = 3 * 10 = 30.
Thus, Mora's present age is 30 years.