You roll a six-sided die.
Event A: Roll an odd number.
Event B: Roll a number less than 5.
Find P (A or B) . Express you answer as a fraction in simplest form.
Plz help!!
In this Case, It would be 5/6, as you find that one of the numbers less than five is also a prime number. Making there one prime number apart from the numbers less than five. Add 1+4 and you get 5. Since there are six sides this makes it 5/6
No. That's not how this works . THis is theoretical probability, meaning there are actually 4 numbers less than five. You're doing experimental probability. THis is incorrect
Sure, I'd be happy to help! Let's break it down.
The possible outcomes when you roll a six-sided die are: 1, 2, 3, 4, 5, and 6.
Event A: Roll an odd number. So the outcomes for event A are: 1, 3, and 5.
Event B: Roll a number less than 5. So the outcomes for event B are: 1, 2, 3, and 4.
To find P(A or B), we need to find the probability of event A or event B occurring.
Let's count the outcomes that satisfy either event A or event B:
1, 2, 3, 4, and 5.
Out of the six possible outcomes, five satisfy either event A or event B.
Therefore, P(A or B) = 5/6.
Hope this helps! Remember, if you need any more assistance, I'll be here, juggling my funny answers.
To find the probability of the union of two events (A or B), you need to calculate the sum of their individual probabilities minus the probability of their intersection.
In this case, event A consists of rolling an odd number, which includes the numbers 1, 3, and 5. Since there are six possible outcomes in rolling a six-sided die, the probability of rolling an odd number is given by P(A) = 3/6.
Event B consists of rolling a number less than 5, which includes the numbers 1, 2, 3, and 4. Therefore, the probability of rolling a number less than 5 is given by P(B) = 4/6.
To find the probability of A or B (P(A or B)), we need to consider their intersection. In this case, the intersection of events A and B includes the numbers 1, 3, and 4. So the probability of their intersection is P(A and B) = 3/6.
Calculating the probability of their union can be done using the formula:
P(A or B) = P(A) + P(B) - P(A and B)
Substituting the values we calculated, we have:
P(A or B) = 3/6 + 4/6 - 3/6
Simplifying the expression gives:
P(A or B) = 7/6 - 3/6
Combining the numerators gives:
P(A or B) = 7 - 3 / 6
Thus, the probability of rolling an odd number or a number less than 5 is 4/6 or simplified as 2/3.