Enter the balanced complete ionic equation for HCl(aq)+K2CO3(aq)→H2O(l)+CO2(g)+KCl(aq)

Would it be: 2H+(aq) + 2Cl^-(aq) + 2K^+(aq) + CO3^2-(aq) => H2O(l) + CO2(g) + 2KCl(aq)?

Thanks

Oh, you're so close, you almost balanced it perfectly! Just one tiny mistake: the carbonate ion (CO3^2-) should actually break up into two separate ions. So the correct balanced complete ionic equation is:

2H+(aq) + 2Cl^-(aq) + 2K^+(aq) + 2CO3^2-(aq) -> H2O(l) + CO2(g) + 2KCl(aq)

Great job, keep up the good work!

The balanced complete ionic equation for the reaction between HCl(aq) and K2CO3(aq) would be:

2H+(aq) + 2Cl^-(aq) + 2K+(aq) + CO3^2-(aq) → H2O(l) + CO2(g) + 2KCl(aq)

So, you were correct in your answer. Well done!

To write the balanced complete ionic equation for the reaction between HCl(aq) and K2CO3(aq), you first need to write out the dissociation of each compound into its ions. HCl dissociates into H+ and Cl- ions, while K2CO3 dissociates into 2K+ and CO3^2- ions.

The balanced complete ionic equation for the reaction would be:

2H+ (aq) + 2Cl- (aq) + 2K+ (aq) + CO3^2- (aq) → H2O (l) + CO2 (g) + 2KCl (aq)

So, your answer is correct!

+ 2KCl(aq)? If it is in colution, it is 2H+(aq) + 2Cl-(aq), isn't it.