A glass cup of orange juice is found to be POH of 11•40. Calculate the concentration of hydrogen ion in the juice?
pH +poH =14, pH=14-poH,=14-11.40,=2.60,pH =-log[H+],-log[H+]=2.60, log[H+]=-2.60,antilog of-2.51*10-3
pH + pOH = 14.
Calculate pH.]
Then pH = -log(H^+)
Solve for (H^+)
pOH + pH = 14
... find the pH
10^(- pH) = concentration of hydrogen ion
I don't understand
calculation of the question
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I'm sorry, I don't understand what you are trying to say. Can you please rephrase?
To calculate the concentration of hydrogen ions (H+) in the juice, we need to convert the pOH value into pH and then use the pH to determine the H+ concentration.
The pOH value can be converted into pH using the equation:
pOH + pH = 14
Rearranging the equation, we can isolate the pH value:
pH = 14 - pOH
Let's calculate the pH using the given pOH:
pH = 14 - 11.40
pH = 2.60
Now, we have the pH value of 2.60. To determine the concentration of hydrogen ions (H+), we can use the equation:
[H+] = 10^(-pH)
Let's calculate the concentration of hydrogen ion (H+):
[H+] = 10^(-2.60)
[H+] = 0.00251 mol/L
Therefore, the concentration of hydrogen ion in the juice is 0.00251 mol/L.
Log10[H+]+-Log10[OH+]=2.60
11.40-2.60=8.8