A.The quantity y is partly constant and partly varies inversely as the square of x

B.find the relationship between x and y when x=1,y=11 and when x=2,y=5
C.find the value of y when x=4

Ask your maths teacher this question if he or she does`nt answer then his not good at math or even physics

To find the relationship between x and y when x=1, y=11 and when x=2, y=5, we can set up an equation using the information given.

A tells us that y is partly constant and partly varies inversely as the square of x. This means that we can write the relationship as:

y = k * (1/x^2)

where k is the constant part.

Using the given values, we can substitute them into the equation:

When x=1, y=11:
11 = k * (1/1^2) = k * 1 = k

When x=2, y=5:
5 = k * (1/2^2) = k * (1/4) = k/4

Now we have two equations: k = 11 and k/4 = 5.

We can solve for k by multiplying the second equation by 4:

4 * (k/4) = 5 * 4
k = 20

Now that we have the value of k, we can use it to find the value of y when x=4. Thus, we substitute the values into the equation:

y = k * (1/x^2) = 20 * (1/4^2) = 20 * (1/16) = 20/16 = 5/4 = 1.25

Therefore, when x=4, y equals 1.25.

A. y = m + k/x^2

B. Plug in your numbers to find m and k
C. Now, knowing the constants, plug in x=4 to find y

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when p =36 q =3 and R = 4 caulate q when p =200 and R e

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