A.The quantity y is partly constant and partly varies inversely as the square of x
B.find the relationship between x and y when x=1,y=11 and when x=2,y=5
C.find the value of y when x=4
Ask your maths teacher this question if he or she does`nt answer then his not good at math or even physics
To find the relationship between x and y when x=1, y=11 and when x=2, y=5, we can set up an equation using the information given.
A tells us that y is partly constant and partly varies inversely as the square of x. This means that we can write the relationship as:
y = k * (1/x^2)
where k is the constant part.
Using the given values, we can substitute them into the equation:
When x=1, y=11:
11 = k * (1/1^2) = k * 1 = k
When x=2, y=5:
5 = k * (1/2^2) = k * (1/4) = k/4
Now we have two equations: k = 11 and k/4 = 5.
We can solve for k by multiplying the second equation by 4:
4 * (k/4) = 5 * 4
k = 20
Now that we have the value of k, we can use it to find the value of y when x=4. Thus, we substitute the values into the equation:
y = k * (1/x^2) = 20 * (1/4^2) = 20 * (1/16) = 20/16 = 5/4 = 1.25
Therefore, when x=4, y equals 1.25.
A. y = m + k/x^2
B. Plug in your numbers to find m and k
C. Now, knowing the constants, plug in x=4 to find y