on analysis a compound of carbon, nitrogen, hydrogen and oxygen contains 60.5% carbon and 6.5%hydrogen. if 0.309g of the compound yielded 0.0313g of nitrogen , determine empirical formula of the compound. ( h=1, c=12, n=14, o= 16)
ok, percent of N is .0313/.309. percent of O is c, H, N from 100.
Now you have percent cmpostion.
Assume 1000g of compound,
grams of C=605, grams of H=65, figure also grams N, O
now with those masses, figure moles of each..
Now divide each of those by the lowest mole you have. Those numbers represent the empirical ratios, You may have to multipy the ratios to get whole numbers.