How many moles of O2 are needed to react with 2.50 mol of C2H2?
Thank you so much
Well, it seems like we have a chemistry question over here! Let's grab our lab coats and goggles, and dive right in!
To find out how many moles of O2 are needed to react with 2.50 mol of C2H2 (also known as acetylene), we need to take a look at the balanced chemical equation for the reaction. So, drumroll please...
2 C2H2 + 5 O2 --> 4 CO2 + 2 H2O
From this equation, we can see that we need 5 moles of O2 to react with 2 moles of C2H2. So, if we have 2.50 moles of C2H2, we can set up a simple proportion to find the number of moles of O2 needed:
2.50 mol C2H2 / 2 mol C2H2 = x mol O2 / 5 mol O2
Cross-multiplying, we get:
2.50 mol C2H2 * 5 mol O2 = 2 mol C2H2 * x mol O2
Simplifying, we find:
12.50 mol O2 = 2x mol O2
Dividing both sides by 2, we get:
x = 6.25 mol O2
So, approximately 6.25 moles of O2 are needed to react with 2.50 mol of C2H2. That's a lot of O2! I hope you have enough gas masks to go around!
To determine the moles of O2 needed to react with 2.50 mol of C2H2, we need to refer to the balanced chemical equation for the reaction between C2H2 and O2.
The balanced chemical equation is:
2 C2H2 + 5 O2 → 4 CO2 + 2 H2O
From the equation, we can see that 2 moles of C2H2 react with 5 moles of O2. This means for every 2.50 mol of C2H2, we will need to use a proportion to find the moles of O2.
Proportion:
(2 moles of C2H2 / 5 moles of O2) = (2.50 mol of C2H2 / x moles of O2)
Cross-multiplying the proportion, we get:
(2 moles of C2H2) * (x moles of O2) = (5 moles of O2) * (2.50 mol of C2H2)
Simplifying this equation:
2x = 12.50
x = 12.50 / 2
x = 6.25
Therefore, 6.25 moles of O2 are needed to react with 2.50 mol of C2H2.
To determine how many moles of O2 are needed to react with 2.50 mol of C2H2, we need to look at the balanced chemical equation for the reaction between C2H2 and O2.
The balanced equation is:
2 C2H2 + 5 O2 -> 4 CO2 + 2 H2O
From the equation, we can see that 2 moles of C2H2 react with 5 moles of O2. This is the stoichiometric ratio between C2H2 and O2.
Now, we can set up a proportion to find the number of moles of O2 needed:
(5 moles O2 / 2 moles C2H2) = (x moles O2 / 2.50 moles C2H2)
Cross-multiplying the equation gives us:
5 moles O2 * 2.50 moles C2H2 = 2 moles C2H2 * x moles O2
12.50 moles O2 = 2x moles O2
Simplifying the equation, we find:
x moles O2 = 12.50 moles O2 / 2
x moles O2 = 6.25 moles O2
Therefore, 6.25 moles of O2 are needed to react with 2.50 moles of C2H2.
2C2H2 + 5O2 ==> 4CO2 + 2H2O
2.50 mols C2H2 x (5 mols O2/2 mol C2H2) = ?