The perimeter of a rectangle is 100 feet and the length is 12 feet longer than the width. Find the length and width of the rectangle.
Actually, the left equation already has the value of l, so you have to substitute that into the right equation.
still confused
Remember that the formula for the perimeter of a rectangle is p=2l+2w. You would have to make a system of equations here to solve this problem. It's l=w+12; 100=2l+2w. Solve the left equation and then everything will fall into place. Let me know if you are still stuck.
Wtf is the answer tho
To find the length and width of the rectangle, we can set up a system of equations.
Let's assume the width of the rectangle is x feet. According to the problem, the length is 12 feet longer than the width, so the length would be (x + 12) feet.
The formula for the perimeter of a rectangle is P = 2 * (length + width). Therefore, the perimeter of this rectangle would be given by:
100 = 2 * ((x + 12) + x)
Simplifying this equation, we have:
100 = 2 * (2x + 12)
50 = 2x + 12
2x = 50 - 12
2x = 38
x = 38/2
x = 19
Now that we have found the width, we can substitute this value back into the equation to find the length:
Length = x + 12
Length = 19 + 12
Length = 31
So, the width of the rectangle is 19 feet and the length is 31 feet.