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Five years ago, a mother was twice as old as her son. in 6 years time, the sum of their age will be 82. find their present ages

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3 answers
  1. Present age of son ---- x
    present age of mother --- y

    5 years ago:
    son --- x-5
    mother --- y-5
    y-5 = 2(x-5)
    y-5 = 2x - 10
    2x - y = 5 or y = 2x - 5

    6 years from now:
    son --- x+6
    mother ---- y + 6
    x+6 + y+6 = 82
    x + y = 70
    x + 2x-5 = 70
    3x = 75
    x = 25 , then y = 2x-5 = 45

    state your conclusion

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    👤
    Reiny
  2. Good. Very good

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  3. Good

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