the sum of two numbers is 46. The smaller number is 6 less than the larger number. What are the two numbers?
x - 6 + x = 46
2x = 52
x = 26
The sum of two numbers is 46. The larger number is two less than three times the smaller number. Find the numbers.
Well, let me put on my thinking clown nose for this one! Let's call the smaller number "x" and the larger number "y". According to the information you've given me, we know that:
x + y = 46
x = y - 6
Now, we can replace x in the first equation with y - 6:
(y - 6) + y = 46
Simplifying this equation, we get:
2y - 6 = 46
2y = 52
y = 26
Now we can substitute y back into the equation x = y - 6:
x = 26 - 6
x = 20
Therefore, the two numbers are 20 and 26. Tada!
Let's assign variables to the two numbers. Let x represent the larger number, and y represent the smaller number.
According to the problem, the sum of the two numbers is 46, so we have the equation:
x + y = 46
We also know that the smaller number is 6 less than the larger number, which gives us the equation:
y = x - 6
Now we can solve the system of equations by substituting the value of y from the second equation into the first equation:
x + (x - 6) = 46
2x - 6 = 46
2x = 46 + 6
2x = 52
x = 52 / 2
x = 26
Now that we have found the value of x, we can substitute it back into the second equation to find y:
y = 26 - 6
y = 20
Therefore, the larger number is 26 and the smaller number is 20.
To solve this problem, let's assume that the smaller number is represented by 'x' and the larger number is represented by 'y'.
According to the problem, the sum of the two numbers is 46. Therefore, we can create an equation: x + y = 46.
The problem also states that the smaller number is 6 less than the larger number. In other words, x = y - 6.
Now we have a system of two equations:
Equation 1: x + y = 46
Equation 2: x = y - 6
To solve this system, we can substitute Equation 2 into Equation 1 and solve for 'y'.
Replacing x in Equation 1, we get:
(y - 6) + y = 46
Simplifying the equation:
2y - 6 = 46
Adding 6 to both sides:
2y = 52
Dividing both sides by 2:
y = 26
Now that we have the value of 'y', we can substitute it back into Equation 2 to find 'x'.
x = y - 6
x = 26 - 6
x = 20
Therefore, the two numbers are 20 and 26.