Graph the line using a point and a slope. Write the equation of each line.

a line that contains the point (0, −3) and perpendicular to another line whose slope is 2.

y=-1/2x-3

You’re welcome

To graph a line using a point and a slope, you can follow these steps:

1. Start by plotting the given point (0, -3) on the coordinate plane. This point will be on the line you are trying to graph.

2. Determine the slope of the line perpendicular to the given line. The slope of a line perpendicular to another line is the negative reciprocal of the slope of the given line.

Given line slope = 2
Perpendicular line slope = -1/2 (negative reciprocal of 2)

3. Now that you have the slope of the line and a point on the line, use the point-slope form of a linear equation to write the equation of the line. The point-slope form is given by:
y - y1 = m(x - x1)

Substitute the values from the given point (0, -3) and the perpendicular slope (-1/2) into the equation:
y - (-3) = (-1/2)(x - 0)
y + 3 = (-1/2)x

4. Simplify the equation to get the final equation of the line:
y + 3 = (-1/2)x
y = (-1/2)x - 3

Now, you have the equation of the line and can use it to plot additional points to graph the line.

use point-slope for the equation ... y + 3 = -1/2 x

I won't give the equation, but here's some advice to help. Turn the slope of 2 into a fraction. Also, the slope of a perpendicular line is always the negative reciprocal. This should give you the slope, and you can graph the line to find the y-intercept, giving you the equations of the lines.

~Dog_Lover

perpendicular slopes are negative reciprocals

the new line has a slope of ... -1/2

Correction to my Eq; b = y - mx = -3 - (-0 5)0 = -3.

(0, -3), m = -1/2 = -0.5,

Y = mx + b.
m = -0.5.
b = y - mx = -3 - (-0.5)0 = -2.5.