Write a net ionic equation for the reaction that occurs when aqueous solutions of ammonia and hydrobromic acid are combined.

NH3(aq) + HBr(aq) ==> NH4Br(aq)

NH3(aq) + H^+(aq) + Br^-(aq) ==> NH4^+ (aq) + Br^-(aq)
Now cancel the ions common to both sides, namely Br^- to leave
NH3(aq) + H^+(aq) ==> NH4^+(aq)

Sure, here is the net ionic equation for the reaction between ammonia and hydrobromic acid:

NH3 (aq) + HBr (aq) → NH4+ (aq) + Br- (aq)

And remember, always be cautious when mixing ammonia and hydrobromic acid. It's a little bromantic, but the combination can be a bit explosive!

To write the net ionic equation for the reaction between aqueous solutions of ammonia (NH₃) and hydrobromic acid (HBr), we first need to write the balanced chemical equation.

The balanced chemical equation for the reaction is:

NH₃(aq) + HBr(aq) → NH₄Br(aq)
(Ammonia + Hydrobromic acid → Ammonium bromide)

To write the net ionic equation, we need to exclude the spectator ions. The spectator ions are the ones that do not undergo any change during the reaction and appear as ions on both sides of the equation.

In this reaction, the spectator ion is the NH₄⁺ ion, which is present on both the reactant and the product side of the equation.

The net ionic equation for the reaction is:

NH₃(aq) + H⁺(aq) + Br⁻(aq) → NH₄⁺(aq) + Br⁻(aq)
(Ammonia + Hydrogen ion + Bromide ion → Ammonium ion + Bromide ion)

Therefore, the net ionic equation for the reaction between aqueous solutions of ammonia and hydrobromic acid is NH₃(aq) + H⁺(aq) + Br⁻(aq) → NH₄⁺(aq) + Br⁻(aq).

To write a net ionic equation for a reaction, you first need to determine the balanced chemical equation for the reaction between ammonia (NH3) and hydrobromic acid (HBr).

The balanced chemical equation for the reaction can be written as follows:

NH3 (aq) + HBr (aq) -> NH4Br (aq)

Next, we determine the ionic equation by breaking down all aqueous compounds into their constituent ions. In this case, ammonia remains as a molecule in solution, but hydrobromic acid dissociates completely into its constituent ions:

NH3 (aq) + H+ (aq) + Br- (aq) -> NH4+ (aq) + Br- (aq)

Finally, we write the net ionic equation by removing the spectator ions, which are the ions that appear on both sides of the equation and do not take part in the actual chemical reaction. In this case, the spectator ions are the bromide ions (Br-), which are found on both sides of the equation. Therefore, the net ionic equation is:

NH3 (aq) + H+ (aq) -> NH4+ (aq)