A man who weighs 600 N is sitting in a chair with his feet on the floor and arms resting on the armrests. The chair weighs 100 N. Each armrest exerts an upward force of 25.0 N on his arms, and the seat exerts an upward force of 500 N. What force does the floor exert on his feet?
A man who weighs 600 N is sitting in a chair with his feet on the floor and arms
force of 25.0 N on his arms, and the seat exerts an upward force of 500 N. What
resting on the armrests. The chair weighs 100 N. Each armrest exerts and upward
force does the floor exert on his feet?
The figure shows two particles A and B, of mass m kg and 0.4 kg respectively,
to a line of greatest slope of the plane. The particle B hangs freely below P. The
system is released from rest with the string taut and B descends with acceleration
plane inclined at 30o to the horizontal. The string passes over a small light smooth
connected by a light inextensible string. Initially A is held at rest on a fixed smooth
pulley P fixed at the top of the plane. The section of the string from A to P is parallel
1/5 g.
Well, it sounds like this guy has really good support from all sides! I mean, his arms have the armrests to hold them up, and his seat has a force of 500 N pushing up on it. Now it's time for the floor to do its job and support his feet.
Let me do some quick math here. If the chair weighs 100 N, and the guy weighs 600 N, that's a total weight of 700 N. Now, if we add up all the upward forces on him: the armrests exert 25 N each, which gives us a total of 50 N. And the seat exerts 500 N.
To find the force the floor exerts on his feet, we need to take into account the net downward force. That would be the total weight minus the total upward forces. So, 700 N - (50 N + 500 N) = 150 N.
Therefore, the floor must exert a force of 150 N on his feet to balance out all the other forces. I hope that clears things up, and remember, being well-supported is important, whether it's in a chair or in life!
To find the force that the floor exerts on the man's feet, we need to consider the forces acting on him in the vertical direction. Let's break down the forces:
1. The force exerted by the man's weight: The man weighs 600 N, so this is the force exerted downwards.
2. The force exerted by the chair: The chair weighs 100 N, so this is the force exerted downwards by the chair.
3. The force exerted by the armrests: Each armrest exerts an upward force of 25.0 N on his arms, so the total force exerted by both armrests on his arms is 25.0 N + 25.0 N = 50.0 N.
4. The force exerted by the seat: The seat exerts an upward force of 500 N.
To find the force that the floor exerts on the man's feet, we need to calculate the net force acting on him in the vertical direction:
Net force = Force upwards - Force downwards
Force upwards = Force exerted by the armrests + Force exerted by the seat
= 50.0 N + 500 N
= 550.0 N
Force downwards = Force exerted by the man + Force exerted by the chair
= 600 N + 100 N
= 700 N
Net force = 550.0 N - 700 N
= -150.0 N
The negative sign indicates that the net force is acting downwards. Therefore, to balance the forces, the floor must exert a force of 150.0 N upwards on the man's feet.
net weight=700N force on the floor.
forceonfloor=feet+chair+armrests
feedforce=700-100-25 (assuming the 25 covers both arms)
feet force=575 N