In a competition 7 points were awarded for each game won and 2 points were deducted for each game lost . Onyango got 86 points .If there were 20 games. How many games did he lose?

Let x for won

Lost 20-x
Then 7x-2(20-x)=86
7x-40+2x=86
9x=126
x=14
He lost 6 games

Let stands k for losses games

then wins games are (20-k)
7(20-k) +2k=86
Games played

Won =x

Loose=20-x
7x-2(20-2x)=86
9x=126
divide by 9
X=14
Loose=20-14=6
Lost=6
won=14

Let lost be x.

Let won be (20-x)
Bracket each and multiply by their values hence
(x)-2=lost
(20-x)7=won
140-7x-2x=86
Substitute
140-9x=86
140-86=9x
54=9x
x=6
Substitute
No.of games lost=6

If there were x losses, then the rest (20-x) were wins, right?

Now add up the points awarded/deducted:
7(20-x) - 2x = 86

I did not get this question please help me

10.8

I got it right

Thank you I didn't understand the question but know I have.

No.of games won=20-6=14