If 7 and 189 are the first and fourth terms of a geometric respectively, find the sum of the first three terms of the progression?

7 r^3 = 189 ... r^3 = 27 ... r = 3

7 + 21 + 63 = ?

91

To find the sum of the first three terms of a geometric progression, we first need to determine the common ratio (r) of the progression.

Given that 7 is the first term (a₁) and 189 is the fourth term (a₄), we can use the formula for the nth term of a geometric progression to find the common ratio (r).

The formula for the nth term of a geometric progression is given by:
aₙ = a₁ * r^(n-1)

Plugging in the values:
a₄ = 7 * r^(4-1) = 7 * r^3

We can rearrange this equation to find the common ratio (r):
r = (a₄ / a₁)^(1/3)

Substituting the values of a₄ = 189 and a₁ = 7 into the equation:
r = (189 / 7)^(1/3) = 3

Therefore, the common ratio (r) of the geometric progression is 3.

To find the sum of the first three terms (S₃) of the progression, we use the formula:
S₃ = a₁ + a₂ + a₃

Given that a₁ = 7 and r = 3, we can substitute these values into the formula:

S₃ = 7 + 7 * 3 + 7 * 3^2
= 7 + 21 + 63
= 91

Therefore, the sum of the first three terms of the geometric progression is 91.

To find the sum of the first three terms of a geometric progression, we can use the formula:

S = a * (1 - r^n) / (1 - r),

where S is the sum of the first n terms, a is the first term, r is the common ratio, and n is the number of terms.

In this case, we are given the first term, a = 7, and the fourth term, t₄ = 189. Since the fourth term is given, we can use it to find the common ratio, r.

We can write the formula for the fourth term:

tₙ = a * r^(n-1).

Substituting n = 4 and t₄ = 189, we get:

189 = 7 * r^(4-1),
189 = 7 * r^3.

Dividing both sides of the equation by 7:

27 = r^3.

Taking the cube root of both sides:

r = ∛(27),
r = 3.

Now, we have the common ratio, r = 3. We can use this to find the sum of the first three terms, S₃.

Using the formula, we have:

S₃ = a * (1 - r^3) / (1 - r).

Substituting a = 7 and r = 3:

S₃ = 7 * (1 - 3^3) / (1 - 3).

Performing the calculations:

S₃ = 7 * (1 - 27) / (1 - 3),
S₃ = 7 * (-26) / (-2),
S₃ = 7 * 13,
S₃ = 91.

Therefore, the sum of the first three terms of the geometric progression is 91.