a rectangle has sides of length 6.1 cm and 8.1 cm correct to 1 decimal place. Calculate the upper bound for the area of the rectangle as accurately
Th upper bound has to deal with accuracy of the decimal place. SO looking at your question the upper bound for 6.1 one is 6.15 because you want to try to get it as high as possible without being to close to 6.2. same for 8.1 is 8.15
6.15 * 8.15 = 50.1225
A rectangle has sides of 6.1 and 8.1 correct to 1 decimal place,Calculate the upper bound for the area of the rectangle as accurately as possible
really helpful thank you
A rectangle has sides of length 6.1and8.1cm correct to 1 decimal place ,Complete the statement about the perimeter of the rectangle.
A rectangle has sides of length 6.1cm and 8.1cm correct to 1 decimal place .Complete the statement about the perimeter of the rectangle.
To find the upper bound for the area of the rectangle, we need to consider the maximum possible values for its side lengths. In this case, the side lengths are given as 6.1 cm and 8.1 cm, correct to 1 decimal place.
To calculate the upper bound for the area, we need to consider the upper bound for each side length. For the first side, 6.1 cm, we need to consider the maximum possible value that can be rounded to 6.1 cm. Since the given measurement is correct to 1 decimal place, the maximum possible value for the first side length would be 6.15 cm (rounded to one decimal place).
Similarly, for the second side, 8.1 cm, the maximum possible value that can be rounded to 8.1 cm would be 8.15 cm.
Now, we can calculate the upper bound for the area of the rectangle using these maximum values:
Upper bound for length = 6.15 cm
Upper bound for width = 8.15 cm
Area = Length x Width
Area = 6.15 cm x 8.15 cm
Area = 50.1225 cm²
Hence, the upper bound for the area of the rectangle, as accurately as possible, is 50.1225 cm².