This was originally posted at the end of another student's post.
The pet store sells hamsters, parrots, and rabbits.
There are 3 more rabbits than parrots.
There are 25 pets in all.
How many hamsters, parrots, and rabbits does the pet store have?
i'm very frustrated. Help me out. I'm in 5th grade
0 0
posted by Fareeha
today at 9:00pm
The reason for your frustration is probably because there is not enough information to solve the problem.
25 pets in all , and 3 more rabbits than parrots
So, anywhere from one parrot and four rabbits, with twenty hamsters
... to ten parrots and thirteen rabbits, with two hamsters.
if your in 5th grade then why does your name sound like a teachers name🤨
To solve this problem, we can use algebraic equations. Let's assign variables to the number of hamsters, parrots, and rabbits.
Let's say the number of hamsters is H, the number of parrots is P, and the number of rabbits is R.
From the given information, we know that there are 3 more rabbits than parrots, so we can write the equation: R = P + 3.
We also know that there are a total of 25 pets in all, so the equation would be: H + P + R = 25.
Now, we can use substitution to solve these equations.
First, let's substitute the value of R from the first equation into the second equation:
H + P + (P + 3) = 25
Combining like terms:
H + 2P + 3 = 25
Subtracting 3 from both sides of the equation:
H + 2P = 22
Now we have two equations:
R = P + 3
H + 2P = 22
To solve this system of equations, we can use a method called elimination. To eliminate the H variable, we can multiply the second equation by -1:
-H - 2P = -22
Now, let's add the two equations together:
P + 3 -H - 2P = 25 - 22
Simplifying further:
-H - P + 3 = 3
Subtracting 3 from both sides:
-H - P = 0
Multiplying this equation by -1:
H + P = 0
Now, we can add this equation to the second equation we had earlier:
H + 2P = 22
H + P = 0
Adding the equations together:
H + 2P + H + P = 22 + 0
Combining like terms:
2H + 3P = 22
Now, we have a new equation:
2H + 3P = 22
We can solve this equation to find the values of H and P.
Since you mentioned you are in 5th grade, let's try trial and error to guess the values of H and P.
Let's start with H = 0 and P = 0:
2(0) + 3(0) = 0
This does not equal 22, so let's try another guess.
Let's try H = 0 and P = 3:
2(0) + 3(3) = 9
This still does not equal 22, so let's try another guess.
Let's try H = 1 and P = 0:
2(1) + 3(0) = 2
Still not equal to 22, so let's try another guess.
Let's try H = 2 and P = 0:
2(2) + 3(0) = 4
Still not equal to 22, so let's try another guess.
Let's try H = 0 and P = 1:
2(0) + 3(1) = 3
Still not equal to 22, so let's try another guess.
Let's try H = 5 and P = 0:
2(5) + 3(0) = 10
Still not equal to 22, so let's try another guess.
Let's try H = 0 and P = 7:
2(0) + 3(7) = 21
Still not equal to 22, so let's try another guess.
Let's try H = 11 and P = 0:
2(11) + 3(0) = 22
That's it! We found the solution. The number of hamsters is 11, parrots is 0, and rabbits is 11.
So, the pet store has 11 hamsters, 0 parrots, and 11 rabbits.
I hope this explanation helps you understand how to solve this problem step by step. If you have any further questions, feel free to ask!