One medium circle and one small circle touch each other, and each circle touches the larger circle.
The figure shows two circles of different radius inscribed in a larger circle. The two circles are drawn such that both touch the circle as well as each other without overlapping. The radius of the larger circle inscribed in the circle is labeled as 9 centimeters and the radius of the smaller circle inscribed in the circle is labeled as 4 centimeters. The region inside the circle not covered by the two circles is shaded.
Which is the area of the shaded region?
A.72 π square centimeters
B.97 π square centimeters
C.26 π square centimeters
D.169 π square centimeters
more description needed
Two small circles can be placed inside the larger circle in many ways. All we can be sure of from your description is that the diameter of the other small circle cannot be greater than 10 cm.
In any case, the area a = πr^2 for each circle.
So, the area of the other circle is at most 25π
81π - 16π - 25π = 40π
That is the minimum shaded area.
what is the answer
tysm also the one i posted before this im confused on what the answer is
ESTIMATE BY ROUNDING OF TO NEAREST HUNDREDS THE NUMBER IS 673 - 258
BSRKV SCHOOL TIME TEXT BOOK
To find the area of the shaded region, we need to calculate the area of the larger circle and the two smaller circles and then subtract them from each other.
1. The area of a circle is given by the formula A = πr^2, where A is the area and r is the radius.
2. To find the area of the larger circle, we use the radius labeled as 9 centimeters:
A1 = π(9)^2
3. To find the area of the smaller circle, we use the radius labeled as 4 centimeters:
A2 = π(4)^2
4. Since the two smaller circles touch each other and the larger circle, the total area of the two smaller circles is:
A3 = 2 * A2
5. Finally, to find the shaded region area, we subtract the sum of the areas of the two smaller circles from the area of the larger circle:
Shaded Area = A1 - A3
Now, let's calculate:
A1 = π(9)^2 = 81π
A2 = π(4)^2 = 16π
A3 = 2 * A2 = 2 * 16π = 32π
Shaded Area = 81π - 32π = 49π
The area of the shaded region is 49π square centimeters.
Unfortunately, none of the given answer choices match the calculated area. Please double-check the question or provide additional information to calculate the correct answer.