A machine has a velocity of 6 and is 80% efficient.what effort will be needed to lift a load of 300N with the aid of this machine?
A machines has a velocity ration 6 and it efficiency 75%.what effort would be needed to sift load 300n with the aid of this machine
80% * effort = 300N / 6
Yes
e=M.A./V.R.=(L/E)/V.R.
e=80%
80/100=(300/E)/6. (Cross multiply)
E=30000/480
:E=65.25
Any questions send to this no. Below
08030583848
e=M.A./V.R.=(L/E)/V.R.
e=80%
80/100=(300/E)/6. (Cross multiply)
E=30000/480
:E=6.25
Any questions send to this no. Below
08030583848
E=62.5
The solution
Victor
To determine the effort required to lift a load with the aid of a machine, we can use the equation:
Effort = (Load / Efficiency) - Friction
Given:
Velocity of the machine (V) = 6 (Units are not specified, assuming meters per second)
Efficiency (E) = 80% or 0.8 (expressed as a decimal)
Load (L) = 300N
First, we need to calculate the friction. Since the question does not provide information about the friction, we will assume there is none, or it is negligible. Therefore, we can ignore the friction term in our equation.
Effort = (Load / Efficiency)
Substituting the given values into the equation:
Effort = (300N / 0.8)
Effort = 375N
Therefore, the effort required to lift the load of 300N with the aid of this machine will be 375N.