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Calculate the mass of displaced water when a piece of 30 cm thick iceberg with surface area 1000cm^2 floats on water

Given(density of ice=0.9g/cm^3 &density of water=1gm/cm^3

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  1. Vi = As * h = 1000 * 30 = 30,000 cm^3 = Vol. of the ice.

    Vb = (Di/Dw) * Vi = (0.9/1.0) * 30,000 = 27,000 cm^3 = Vol. below surface - Vol. of water displaced.

    27,000cm^3 * 1g/cm^3 = 27,000 grams = 27 kg = Mass of water displaced.

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  2. Best Answer, But You have to improve in writing line by line. Which help us in better Understanding.

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