Please help! ASAP
1. If the integral from 1 to 6 of f of x, dx equals negative 10 and the integral from 3 to 6 of f of x, dx equals negative 8, then what is the value of integral from 1 to 3 of f of x, dx?
A. 2
B. 2
C. 18
D. 12
2. Use geometry to evaluate the integral from 0 to 6 of the function f of x, dx for f of x equals 4 for x less than or equal to 6 and equals the quantity 10 minus x for x greater than 6. (THIS IS THE ONE I NEED THE MOST HELP ON!!)
A. 4
B. 8
C. 16
D. 24
Thank you in advance! I really appreciate it :)
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2 answers

32 isn't one of the choices. Only those four
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answered by Justin 
#1 break [1,6] into two intervals. It is easy to see that
∫[1,6] = ∫[1,3] + ∫[3,6]
Now just plug in your numbers
#2 I don't like any of the choices.
Draw the graph, and you will see that you have a rectangle and a triangle, whose areas sum to 32
Or, using your actual calculus, the area is
∫[0,6] 4 dx + ∫[6,10] 10x dx
= 4x[0,6] + 10x  x^2/2 [6,10]
= 24 + (10050)  (6018) = 32
Answer this Question
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