An atom of gold has a mass of approximately 3.25×10^-22 grams. What is the mass of 4000 atoms of gold? Express your answer in scientific notation.
4000(3.25×10^-22)
= 13000×10^-22
= 1.3×10^-18
How many decimals did I move the decimal point from 13000 to 1.3? How did I compensate for this in the 10^-22 ?
4000 atoms of gold? That's quite a gold rush! Well, each atom of gold weighs approximately 3.25×10^-22 grams. So, if we multiply the mass of one atom by the number of atoms you have, we get the total mass.
3.25×10^-22 grams/atom × 4000 atoms = 1.3×10^-18 grams
So, the mass of 4000 atoms of gold is approximately 1.3×10^-18 grams. That's a teeny, tiny amount of gold. Don't go spending it all in one place!
To find the mass of 4000 atoms of gold, you need to multiply the mass of one atom by 4000.
Step 1: Multiply the mass of one gold atom by 4000:
(3.25 × 10^-22 grams) × (4000) = 1.3 × 10^-18 grams
Therefore, the mass of 4000 atoms of gold is approximately 1.3 × 10^-18 grams.
To find the mass of 4000 atoms of gold, we first need to calculate the mass of one gold atom and then multiply it by 4000.
Given that an atom of gold has a mass of approximately 3.25×10^-22 grams, we can express it as 3.25 × 10^(-22) g.
To calculate the mass of 4000 atoms of gold, you can multiply this mass by 4000:
Mass of 4000 atoms of gold = 3.25 × 10^(-22) g × 4000
To multiply two numbers written in scientific notation, you can multiply the coefficients (the numbers before the powers of 10) and then add the exponents:
3.25 × 10^(-22) g × 4000 = (3.25 × 4000) × (10^(-22) × 1)
Now, calculate the product of the coefficients:
3.25 × 4000 = 13000
Multiply the powers of 10:
10^(-22) × 1 = 10^(-22)
Combine the result:
13000 × 10^(-22)
Finally, express the answer in scientific notation:
Mass of 4000 atoms of gold = 1.3 × 10^(-18) grams