what mass of Cu(IO3)2 can be formed from 0.650g ofCuSO4.5H2O

molar mass CuSO4.5H2O = ? = Y

molar mass Cu(IO3)2 = ? = Z
0.650 g CuSO4.5H2O x (Z/Y) = ?

To determine the mass of Cu(IO3)2 that can be formed from 0.650g of CuSO4·5H2O, we first need to write and balance the chemical equation for the reaction between CuSO4·5H2O and KIO3.

The balanced chemical equation is:

CuSO4·5H2O + 2KIO3 → Cu(IO3)2 + K2SO4 + 5H2O

From the balanced equation, we can see that the molar ratio between CuSO4·5H2O and Cu(IO3)2 is 1:1. This means that for every 1 mol of CuSO4·5H2O, we'll get 1 mol of Cu(IO3)2.

Now we can calculate the molar mass of CuSO4·5H2O and Cu(IO3)2:

Molar mass of CuSO4·5H2O = (1 mol Cu × atomic mass of Cu) + (1 mol S × atomic mass of S)
+ (4 mol O × atomic mass of O) + (5 mol H × atomic mass of H2O)

Molar mass of CuSO4·5H2O = (1 mol × 63.55 g/mol) + (1 mol × 32.07 g/mol)
+ (4 mol × 16.00 g/mol) + (5 mol × 18.02 g/mol)

Molar mass of CuSO4·5H2O = 249.685 g/mol

Since the molar ratio is 1:1, the mass of Cu(IO3)2 formed will be the same as the mass of CuSO4·5H2O used.

Therefore, 0.650 g of CuSO4·5H2O can form 0.650 g of Cu(IO3)2.

To find the mass of Cu(IO3)2 that can be formed from 0.650g of CuSO4.5H2O, you need to follow these steps:

Step 1: Determine the molar mass of CuSO4.5H2O.
- The molar mass of CuSO4 is calculated as follows:
- Copper (Cu) has a molar mass of 63.55 g/mol.
- Sulfur (S) has a molar mass of 32.07 g/mol.
- Oxygen (O) has a molar mass of 16.00 g/mol.
- Hydrogen (H) has a molar mass of 1.01 g/mol.
- Since there are 5 water molecules (H2O) in CuSO4.5H2O, you need to multiply the molar mass of water by 5.
- Calculate the molar mass of CuSO4: 63.55 g/mol + 32.07 g/mol + (4 × 16.00 g/mol) = 159.61 g/mol.
- Calculate the molar mass of 5H2O: 5 × (2 × 1.01 g/mol + 16.00 g/mol) = 90.10 g/mol.
- Add the molar masses of CuSO4 and 5H2O to find the molar mass of CuSO4.5H2O:
- CuSO4 molar mass + 5H2O molar mass = 159.61 g/mol + 90.10 g/mol = 249.71 g/mol.

Step 2: Find the number of moles of CuSO4.5H2O.
- The number of moles can be calculated using the formula:
- Moles = Mass / Molar Mass.
- Substitute the given mass of CuSO4.5H2O into the formula:
- Moles = 0.650g / 249.71 g/mol = 0.0026 mol.

Step 3: Determine the stoichiometry of the reaction.
- The stoichiometry of the reaction gives the ratio of moles between the reactant (CuSO4.5H2O) and the product (Cu(IO3)2).
- The balanced equation for the reaction is:
- 3CuSO4.5H2O + 2NaIO3 + 2H2SO4 → 3Cu(IO3)2 + 5H2O + 2Na2SO4.
- From the equation, you can see that 3 moles of CuSO4.5H2O react to yield 3 moles of Cu(IO3)2.

Step 4: Calculate the moles of Cu(IO3)2.
- Since the stoichiometry ratio is 1:1 between CuSO4.5H2O and Cu(IO3)2, the number of moles of Cu(IO3)2 formed will be equal to the number of moles of CuSO4.5H2O.
- Therefore, the moles of Cu(IO3)2 = 0.0026 mol.

Step 5: Find the mass of Cu(IO3)2.
- Use the formula:
- Mass = Moles × Molar Mass.
- The molar mass of Cu(IO3)2 is calculated as follows:
- Copper (Cu) has a molar mass of 63.55 g/mol.
- Iodine (I) has a molar mass of 126.90 g/mol.
- Oxygen (O) has a molar mass of 16.00 g/mol.
- Calculate the molar mass of Cu(IO3)2: 63.55 g/mol + (2 × 126.90 g/mol) + (6 × 16.00 g/mol) = 426.25 g/mol.
- Substitute the moles of Cu(IO3)2 into the formula:
- Mass = 0.0026 mol × 426.25 g/mol = 1.107 g.

Therefore, the mass of Cu(IO3)2 that can be formed from 0.650g of CuSO4.5H2O is approximately 1.107g.